Does somebody know how to do this?

a stem and leaf display describes two-digit integers between 20 and 80. for one one of the classes displayed, the row appears as

allochka39001 [22]

Answer:

52, 50, 54, 54, 56

Explanation:

The "stem" in this scenario is the tens digit of the number. Each "leaf" is the ones digit of a distinct number with the given tens digit.

5 | 20446 represents the numbers 52, 50, 54, 54, 56

8 0

3 years ago

C#: Arrays - Ask the user how many students names they want to store. You will create two parallel arrays (e.g. 2 arrays with th

zhenek [66]

Answer:

using System;
public class Program
{
public static void Main()
{
Console.WriteLine("Enter number of students: ");
int num = Convert.ToInt32(Console.ReadLine());
string [] firstName = new string[num];
string [] lastName = new string[num];
for(int i=0 ; i < num; i++){
Console.WriteLine("Enter first name: ");
firstName[i] = Console.ReadLine();
Console.WriteLine("Enter last name: ");
lastName[i] = Console.ReadLine();
}
for(int j=0; j < num; j++){
Console.WriteLine(lastName[j] + "," + firstName[j]);
}
}
}

Explanation:

Firstly, prompt user to enter number of student to be stored (Line 6- 7). Next, create two array, firstName and lastName with num size (Line 8-9).

Create a for-loop to repeat for num times and prompt user to enter first name and last name and then store them in the firstName and lastName array, respectively (Line 11 - 17).

Create another for loop to traverse through the lastName and firstName array and display the last name and first name by following the format given in the question (Line 19 - 21).

4 0

2 years ago

For a cylindrical annulus whose inner and outer surfaces are maintained at 30 ºC and 40 ºC, respectively, a heat flux sensor mea

miskamm [114]

Answer:

$k=0.12\ln(r_2/r_1)$ $\frac {W}{ m^{\circ} C}$

where $r_1$ and $r_2$ be the inner radius, outer radius of the annalus.

Explanation:

Let $r_1$ , $r_2$ and $L$ be the inner radius, outer radius and length of the given annulus.

Temperatures at the inner surface, $T_1=30^{\circ}C\\$ and at the outer surface, $T_2=40^{\circ}C$ .

Let q be the rate of heat transfer at the steady-state.

Given that, the heat flux at r=3cm=0.03m is

$40 W/m^2$ .

$\Rightarrow \frac{q}{(2\pi\times0.03\times L)}=40$

$\Rightarrow q=2.4\pi L \;W$

This heat transfer is same for any radial position in the annalus.

Here, heat transfer is taking placfenly in radial direction, so this is case of one dimentional conduction, hence Fourier's law of conduction is applicable.

Now, according to Fourier's law:

$q=-kA\frac{dT}{dr}\;\cdots(i)$