Answer:
The magnitude and direction of the force between the two charges is 497.66 N in opposite direction.
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = 1.4×10¯³ C
Charge 2 (q₂) = 9.1×20¯⁴ C
Distance apart (r) = 4.8 m
Force (F) =?
NOTE: Electric constant (K) = 9×10⁹ Nm²/C²
The magnitude of the force between the two charges can be obtained as follow:
F = Kq₁q₂ / r²
F = 9×10⁹ × 1.4×10¯³ × 9.1×20¯⁴ / 4.8²
F = 11466 / 23.04
F = 497.66 N
Thus, the magnitude of the force is 497.66 N.
Since both charges has the same sign (i.e they both positive), the force between them will be a force of repulsion. Hence the force will be in opposite direction.
Answer:
B) approaches infinity
Explanation:
The capacitive reactance of an AC capacitor is given by;
Where;
C is the capacitance
f is the frequency of the ac voltage
Therefore, as the frequency of the ac voltage across a capacitor approaches zero, the capacitive reactance of that capacitor approaches infinity.
The correct option is (B) approaches infinity
The forces of gravity between two objects are smaller when the objects are farther apart.
