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erma4kov [3.2K]
2 years ago
6

Explain the purpose of a three-valve manifold in closed tank level measurement installations.

Physics
1 answer:
mamaluj [8]2 years ago
7 0

Answer:

A three valve manifold serves to protect the capsule from being exposed to pressures above the acceptable range and also enables transmitter isolation from the loop of the process

In closed tank level measurement installations the pressure of the gas if presence of gas on top of the liquid will need to be taken account by the use of a reference connection from the level transmitter to the tank top. The valve used in pressure equalization is kept close when the process system is operating normally.

In the event that the transmitter is removed or put into service, it is necessary to ensure that the gas phase which is at the higher pressure is does not over-range the Differential Pressure DP capsule

Explanation:

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A steel wire of length 4.7 m and cross section 3 x 103 m2 stretches by the same amount as a copper wire of length 3.5 m and cros
EleoNora [17]

Answer:

The ratio of the young's modulus of steel and copper is 1.79\times10^{-2}

(c) is correct option.

Explanation:

Given that,

Length of steel wire = 4.7 m

Cross sectionA = 3\times10^{-3}\ m^2

Length of copper wire = 3.5 m

Cross sectionA = 4\times10^{-5}\ m^2

We need to calculate the ratio of young's modulus of steel and copper

Using formula of young's modulus for steel wire

Y=\dfrac{\dfrac{F}{A}}{\dfrac{\Delta l}{l}}

Y_{s}=\dfrac{Fl_{s}}{A_{s}\Delta l}....(I)

The young's modulus for copper wire

Y_{c}=\dfrac{Fl_{c}}{A_{c}\Delta l}....(II)

From equation (I) and (II)

The ratio of the young's modulus of steel and copper

\dfrac{Y_{s}}{Y_{c}}=\dfrac{\dfrac{Fl_{s}}{A_{s}\Delta l}}{\dfrac{Fl_{c}}{A_{c}\Delta l}}

\dfrac{Y_{s}}{Y_{c}}=\dfrac{A_{c}\times l_{s}}{A_{s}\times l_{c}}

\dfrac{Y_{s}}{Y_{c}}=\dfrac{4\times10^{-5}\times4.7}{3\times10^{-3}\times3.5}

\dfrac{Y_{s}}{Y_{c}}=1.79\times10^{-2}

Hence, The ratio of the young's modulus of steel and copper is 1.79\times10^{-2}

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The amount of force needed to sustain motion of a rock in outer space is
BartSMP [9]

Answer:

0 N

Explanation:

According to Newton's first law, object subjected to no force or 0 net force will stay in the same motion. In outer space, there's no gravity or air resistance. So if the net force is 0, a rock in motion would be still in motion forever without a need of an extra force to sustain it.

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I believe the answer is A. hope this helps :)
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What is the purpose of an experiment design?
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