Answer:
Explanation:
This problem is approached using Coulomb's law of electrostatic attraction which states that the force F of attraction or repulsion between two point charges, 
and 
is directly proportional to the product of the charges and inversely proportional to the square of their distance of separation R.
where k is the electrostatic constant.
We can make k the subject of formula as follows;
Since k is a constant, equation (2) implies that the ratio of the product of the of the force and the distance between two charges to the product of charges is a constant. Hence if we alter the charges or their distance of separation and take the same ratio as stated in equation(2) we will get the same result, which is k.
According to the problem, one of the two identical charges was altered from 
to 
and their distance of separation from 
to 
, this also made the force between them to change from 
to 
. Therefore as stated by equation (2), we can write the following;
Therefore;
From equation (4) we now make the new force the subject of formula as follows;
then cancels out from both side of the equation, hence we obtain the following;
From equation (4) we can now write the following;
This could also be expressed as follows;
Work = Force x distance
(10 pounds)(2 feet)
Work = 20 foot-pounds of work
hope this helps :)
3. 2 meters per second 4. i think object 7. i’ll try to figure it out 8. .77 9. 25km 10. 10m each second
The total resistance of an electric circuit with resistors widener series in the sum of the individual resistances:
Each resistor in a series circuit has a same amount of current flowing through it.
Each resistor in a parallel circuit has the same for voltage of the source applied to it.
When was this is are connected in parallel, the supply current is equal to the sum of the current through each resistor. In other words the currents in the branches of a parallel circuit add up to the supply current. When resistors are connected in parallel they have the same potential differences across them.
