Answer:
<h2><em>220.698Hz</em></h2>Explanation:
The fundamental frequency f₀ is expressed as f₀ =V/2L where;
V is the speed of the string =
m is the mass of the string
L is the length of the string
T is the tension in the string
f₀ =
Given datas
m = 5.69g = 0.00569 kg
T = 440N
L = 0.630 m
Required
Fundamental frequency of the steel piano wire f₀
<em>Hence the frequency of the fundamental mode of vibration of the steel piano wire stretched to a tension of 440N is 220.698Hz</em>
Answer:
Characteristic time τ=20 s
When V = 15 m/s
t = 6.66 s
When V = 10 m/s
t = 20 s
When V = 5 m/s
t = 60 s
Explanation:
Given that
c=0.20 N/m(m/s)2
m = 80 kg
Vo=20m/s
Characteristic time τ=m/cvo.
Characteristic time τ=20 s
We know that velocity after t time given as follows
When V = 15 m/s
t = 6.66 s
When V = 10 m/s
t = 20 s
When V = 5 m/s
t = 60 s
George's speed per second is 76.92 m/s
George's velocity in meters per second was 38.46 m/s (North)
<u>Explanation:</u>
When dividing the total distance covered by object by time, we get the value for average speed.
<u>Given:</u>
t = 13 seconds
Calculate the distance without consideration of motion’s direction. So, the distance walks 750 m north first, and then turn around walks 250 m south, so the total distance covered is
d = 750 + 250 = 1000 meters
To find the rate per second, simply divide the distance by the time.
In given case, the students walks 750 m north first, and then turn around walk 250 m south. The displacement is the distance in a straight line between the initial and final position: therefore, in this case, the displacement is
d = 750 (north) - 250 (south) = 500 m (north)
The time taken is t = 13 s
So, the average velocity is (North)
And the direction is north (the same as the displacement).