All categories

3 years ago

Which appliances uses the larger current, a toaster or a desk lamp?

Physics

2 answers:

nydimaria [60]3 years ago

7 0

Answer:

DeskLamp

Explanation:

You're average toaster uses so much more electricity than the average desk lamp. 2 slice toasters I believe uses about 1000 watts? And 4 slice uses 1600. The brightest lightbulbs tend to run on 100 watts so just imagine a lightbulb with 1600 watts. (There's a video of a man cranking the watts to a 1000 watt lightbulb up to millions until it pops) Lightbulbs have a very far range in the amounts of energy they can take in. Here is a simplified answer-

On average- the toaster would use the most watts in terms of use

In other circumstances- The lightbulb would be the case.

So yeah,

It's Desklamps. They're really powerful.

scoundrel [369]3 years ago

5 0

Answer: Desklamp
Depending on the light it can use up to 12%
And closest to a toster was and electrical oven which was only 2% of current... So I'm pretty sure the answer would be a Desklamp

You might be interested in

A 2.5-cm-diameter parallel-plate capacitor has a 2.2 mm spacing. The electric field strength inside the capacitor is 6.0×104 V/m

vladimir2022 [97]

Explanation:

The given data is as follows.

Separation between two plates, d = 2.2 mm = $2.2 \times 10^{-3} m$

Electric field strength inside the capacitor, E = $6.0 \times 10^{4} V/m$

Therefore, we will calculate the potential difference across the capacitor as follows.

V = Ed

= $6.0 \times 10^{4} V/m \times 2.2 \times 10^{-3} m$

= 1.32 V

Thus, we can conclude that the potential difference across the given capacitor is 1.32 V.

3 0

3 years ago

Que fracción de luz que llega directa a una lamina de vidrio se refleja en la primera superficie?

Veseljchak [2.6K]

Answer:

unos 40 o30 pienso

Explanation:

7 0

3 years ago

(1) Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy so

malfutka [58]

Solution :

The relationship between the strength of magnetic field and the radiusof a charged particle's path is obtained through Newton's second law, which is given by :

F = ma

F = qvB and $a=\frac{v^2}{r}$

Substituting these values in the second law of Newton,

$qvB=\frac{mv^2}{r}$

Now solving for B, we get:

$B = \frac{mv}{rq}$

$=\frac{(1.67 \times 10^{-27})(5 \times 10^{7})}{2\times 1.6 \times 10^{-19}}$

= 0.261 T

The field strength can be obtained by using the technology of today.

7 0

3 years ago

Time and velocity are both vectors T/F

Fantom [35]

Time and velocity are both vectors T/F

6 0

3 years ago

14. A block rests on a frictionless table on Earth. After a 20-N horizontal force is applied to the block, it accelerates at 3.9

joja [24]

<span>14. Let's find mass. We know that F = m*a, so m = F/a.m = 20/3,9 m/s^2 = 5,12 kg;We already know the mass, so acceleration will be a = F/m;a = 10/5,12 = 2,0 m/s^2 (approximately);Answer: E.
15. According to the picture given above, let's define all components:These are refer to y: $985N sin(31)= 507;788N cos(32)= 668;411N sin(53)=-328;$
And these are refer to x: $985N cos(31)= 844 788N sin(32)= -417 411N cos(53)= -247$
And finally let's calculate tan: $tan^-1 (507/844)= 30,98; tan^-1 (668/-417)= -58,02; tan^-1 (-328/-247)= 53,01$
According to these calculations we've got: Sum Fx = 179,4 and Sum Fy = 847. Then let's count magnitude: $Fsum = rad 179^2 + 847^2 = 865$
Then we've got [tex]cos^-1 (179/865) = 77.7 (approximately).
So the most approximate answer is C. 866 N at 78.1° counterclockwise to the x-axis.
16. I think that this question is incomplete because there wasn't mentioned in what end of the chain the tension should be calculated. Anyway I'll help you with both bottom and top ends. We will use the basic formula W=m*g; W(bottom) = 175*9.8 = 1715 N; W(top) = (175+12)*9.8 = 1833 N; So you should choose between B. 1830 N or D. 1720 N. But I think the most possible answer is B.
17. I am definitely sure that A diagram generates the most tension in one chain. So the answer is C. The box is held by 1 chain and have all its weight.
18. I think that each planet would move in a straight line at constant speed, because there will be a zero gravity condition and there won't any impact on the planets.
19. According to the Work-Energy Theorem we have:1/2*1200*2^2 = 2400 (J);Then let's count the average force according to the formula: Work = F*D where D is displacement.F = 2400/ 0.15 = 16000 (N)
So the answer is B. 1.6 × 10^4 N
20. If my memory serves me well, magnetism is the force that can act through empty space. It's one aspect of the combined electromagnetic force. So the answer is A.
21. According to the illustration given above, I think we should use formula F = m*g; Let's count m. m = 5 kg - 0,6 kg = 4,4 kg; Then we have everything to count force:F = 4,4 * 9,8 = 43,1 N. So the most approximate answer is D. 43 N.
22. I am definitely sure that the answer is C. on Earth at sea level. Because weight has the formula W=mg. And on the earth surface the magnitude of g is higher that everywhere so the greatest weight is on Earth at sea level.
23. We have everything to calculate the acceleration. According to Newton's second law, the formula is a = F/m;a = 20/40 = 0,5 m/s^2; So the answer is A.
24. According to the definition of action reaction forces, the answer should be: A. The forces are opposite in direction, with the force on the ball much stronger in magnitude.
25. I am pretty sure that we should use Newton’s second law of motion F = m*a. First we should find mass, using formula W=m*g => m = W/g => m = 2400/9.8= 245 kg. Then we can find F.F = m*a;F = 245*12 = 2940 N; Answer: B
</span>

7 0

3 years ago

Read 2 more answers