Question

a student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a

Answer 1

Given:

$Force, f = 12 \frac{kg-m}{sec^{2} }$

$Mass, m = 7 kg$

$Acceleration, a_{1} = 3\;\frac{m}{sec^{2} }$

$a = a_{1}+\frac{f}{m}$

$Substitute\;the\;values\;of\;f,\;m\;and\;a_{1}\;in\;the\;above\;equation,$

$a = 3+\frac{12}{7}$

$a = 3 + 1.714$

Therefore, the acceleration is,

$a = 4.714\;\frac{m}{sec^{2} }$

Explain Acceleration?

An object's rate of changing its velocity is known as its acceleration, which is a vector quantity. If an object's velocity is changing, it is accelerating. When anything moves faster or slower in a straight line, it is said to have been accelerated. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.

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