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alex41 [277]
3 years ago
9

How many atoms are in 5 mole of water? Steps

Chemistry
1 answer:
Vladimir79 [104]3 years ago
3 0

Answer: 3.01 x 10^24 atoms

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

So, 1 mole of water = 6.02 x 10^23 atoms

5 moles of water = Z atoms

To get the value of Z, cross multiply

Z x 1 mole = (6.02 x 10^23 atoms x 5 moles)

Z•mole = 30.1 x 10^23 atoms•mole

Divide both sides by 1 mole

Z•mole/1 mole = 30.1 x 10^23 atoms•mole/ 1 mole

Z = 30.1 x 10^23 atoms

[Place the value of Z in standard form]

Z = 3.01 x 10^24 atoms

Thus, there are 3.01 x 10^24 atoms in 5 mole of water

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Answer:

You would need 8 eight packs of water

Explanation:

32  x  2 (seeing as this is the amount of water each person consumes)

= 64 divided by 8 (the amount of water in each pack)

= 8 eight packs of water

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Name two events involving electrons that can result in the formation of chemical bonds between atoms.
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Explanation:

Two events involving electrons are gain and loss of electrons.

When there is gain or loss of electrons between two atoms then it results in the formation of ionic bond.

Whereas when there is sharing of electrons between two atoms then it results in the formation of covalent bond.

Therefore, the chemical bonds formed can be ionic or covalent bonds.

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Onsider the following reaction at equilibrium:
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Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

C(s)+H_2O(l)\leftrightharpoons CO(g)+H_2(g)

A. C is added to the reaction mixture.

If the concentration of reactant specie is increased , according to the Le-Chatlier's principle , the equilibrium will shift in the direction where decrease in concentration of reactant specie occurs. So, on increasing C ,equilibrium will shift in right direction.

B. H_2O is condensed and removed from the reaction mixture.

If the concentration of reactant specie is decreased , according to the Le-Chatlier's principle , the equilibrium will shift in the direction where increase in concentration of reactant specie occurs. So, on removing water vapor ,the equilibrium will shift in left direction.

C. CO is added to the reaction mixture.

If the concentration of product specie is increased , according to the Le-Chatlier's principle , the equilibrium will shift in the direction where decrease in concentration of product specie occurs. So, on increasing CO, the equilibrium will shift in left direction.

D. H_2 is removed from the reaction mixture.

If the concentration of product specie is decreased , according to the Le-Chatlier's principle , the equilibrium will shift in the direction where increase in concentration of product specie occurs. So, on removing hydrogen , the equilibrium will shift in right direction.

5 0
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Answer:

212.5 mL

both the original and the diluted solution have 0.765 moles of KCl

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(637.5 - 425) mL = 212.5 mL

n = (1.8 mol/L)(0.425 L) = 0.765 moles of KCl

since it's a dilution, the diluted solution has the same number of moles as the original solution, 0.765 moles of KCl

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