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3 years ago

How can an iceberg (temperature=0 Celsius) have more energy than a burning match head (temperature=230 Celsius)?

1 answer:

5 0

Temperature is the average energy of each particle and does not really give you an indication of the total internal energy. That being said, total internal energy is the sum of all of the molecule's energy in a given object so it would make sense that an ice berg (having a huge number molecules at a lower average energy) would have more internal energy than a match head (having a much smaller number of molecules at a higher average energy). Basically, the fact that ice bergs tend to be huge and contain much more molecules than a match head, means that ice bergs can have a larger total internal energy which means they store more energy.

I hope this helps.

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Which of the following represents a chemical change?

Snezhnost [94]

The answer is B.) Freezing of water

3 0

2 years ago

Is mixing baking soda and vegetable oil a chemical change or physical change and WHY? PLEASE HELP

skelet666 [1.2K]

It’s a chemical change

3 0

2 years ago

Read 2 more answers

Explain

Trava [24]

There are so many routes by which water can move through the various stages in the water cycle.

<h3>What is the water cycle?</h3>

The water cycle has to do with the route of movement of water in the enviroment. We have to note that there are so many routes by which water can move through the various stages in the water cycle.

The sun supplies the energy that drives the water cycle. This is seen in the fact that the supply of energy from the sun is required for evaporation to take place.

Learn more about water cycle:brainly.com/question/1151425

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6 0

2 years ago

You decide to clean the bathroom. You notice that the shower is covered in a strange green slime . you try to get rid of this sl

Free_Kalibri [48]

The independent variable (IV) is the lemon juice mixture
The dependent variable (DV) is the appearance of the green slime on the shower
The control variable (CV) are time taken to spray, the amount of spray
The experimental group (EG) is the side of the shower sprayed with lemon juice mixture
The control group (CG) is the side of the shower sprayed with water.

INDEPENDENT VARIABLE

Independent variable is the variable of an experiment that is changed by the experimenter in order to bring about a change. It is the variable being tested in the experiment. In this case, the IV is the lemon juice mixture tested on the green slime on the shower.

DEPENDENT VARIABLE:

Dependent variable is the variable that is observed or measured in an experiment. It is also called responding variable. The DV in this case is the appearance of the green slime on the shower.

CONTROL VARIABLE:

Control variable is the variable that is kept constant throughout the experiment for all groups. The CV is the same for all the groups and they include: time taken to spray, the same amount of spray

CONTROL GROUP

Control group is the group that does not receive the independent variable or test in an experiment. In this case, the CG is the side of the shower sprayed with water.

EXPERIMENTAL GROUP:

Experimental group is the group of ab experiment that receives the experimental treatment or independent variable. In this case, the EG is the side of the shower sprayed with lemon juice mixture.

Therefore, the IV, DV, CV, EG and CG of this experiment are as follows:

The independent variable (IV) is the lemon juice mixture
The dependent variable (DV) is the appearance of the green slime on the shower
The control variable (CV) are time taken to spray, the amount of spray
The experimental group (EG) is the side of the shower sprayed with lemon juice mixture
The control group (CG) is the side of the shower sprayed with water.

Learn more: brainly.com/question/17498238?referrer=searchResults

7 0

2 years ago

4.45 kcal of heat was added to increase the temperature of a sample of water from 23.0 °C to 57.8 °C. Calculate

Alona [7]

Answer:

m = 4450 g

Explanation:

Given data:

Amount of heat added = 4.45 Kcal ( 4.45 kcal ×1000 cal/ 1kcal = 4450 cal)

Initial temperature = 23.0°C

Final temperature = 57.8°C

Specific heat capacity of water = 1 cal/g.°C

Mass of water in gram = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 57.8°C - 23.0°C

ΔT = 34.8°C

4450 cal = m × 1 cal/g.°C × 34.8°C

m = 4450 cal / 1 cal/g

m = 4450 g

4 0

2 years ago