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miss Akunina [59]
2 years ago
15

This response to stimuli is very important in protecting the eyes because although they need light to see, too much light can ca

use serious damage. Which of the following best describes the nervous system's role in changing pupil size in response to light?
A.
The nervous system works without the aid of other systems in order to provide a sufficiently rapid response.
B.
The nervous system receives and interprets sensory information from the eyes and signals the muscles of the eyes to perform the response.
C.
The nervous system is a network of electrical impulses that becomes activated after the muscles within the eyes perform the response.
Chemistry
2 answers:
vredina [299]2 years ago
8 0

Answer:

The nervous system receives and interprets sensory information from the eyes and signals the muscles of the eyes to perform the response.

Explanation:

"The involuntary response of pupils dilating and contracting in response to light involves nerves sending impulses to and from the eyes' light receptors, which in turn tell the muscles in the iris to contract or expand." - Study Island

Dimas [21]2 years ago
7 0

A. The nervous system works without the aid of other systems in order to provide a sufficiently rapid response.

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A student would like to determine how heating a liquid changes its volume. The student hypothesizes that the liquid will increas
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The volume of the liquid should be measured before it is heated.  

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Describe relationships between molecules atoms and a grain of sugar
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3 0
3 years ago
the concentration of the radio active isotope potassium-40 in a rock sample is found to be 6.25%. what is the age of the rock
julsineya [31]

Answer:

5.0 x 10⁹ years.

Explanation:

  • It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
  • Half-life time is the time needed for the reactants to be in its half concentration.
  • If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
  • Also, it is clear that in first order decay the half-life time is independent of the initial concentration.
  • The half-life of K-40 = 1.251 × 10⁹ years.

  • For, first order reactions:

<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>

Where, k is the rate constant of the reaction.

t1/2 is the half-life of the reaction.

∴ k =0.693/(t1/2) = 0.693/(1.251 × 10⁹ years) = 5.54 x 10⁻¹⁰ year⁻¹.

  • Also, we have the integral law of first order reaction:

<em>kt = ln([A₀]/[A]),</em>

where, k is the rate constant of the reaction (k = 5.54 x 10⁻¹⁰ year⁻¹).

t is the time of the reaction (t = ??? year).

[A₀] is the initial concentration of (K-40) ([A₀] = 100%).

[A] is the remaining concentration of (K-40) ([A] = 6.25%).

∴ (5.54 x 10⁻¹⁰ year⁻¹)(t) = ln((100%)/( 6.25%))

∴ (5.54 x 10⁻¹⁰ year⁻¹)(t) = 2.77.

∴ t = 2.77/(5.54 x 10⁻¹⁰ year⁻¹) = 5.0 x 10⁹ years.

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