Question

The following redox reaction is conducted with [Al3+] = 0.12 M and [Mn2+] = 1.5 M.

Answer 1

Answer:

0.47V

Explanation:

2 Al(s) + 3 Mn2+(aq) → 2 Al3+(aq) + 3 Mn(s)

n= 6 ( six moles of electrons were transferred)

Q= [Red]/[Ox] but [Red]= 1.5M, [Ox] = 0.12 M

Q= 1.5/0.12= 12.5

From Nernst equation:

E= E°cell- 0.0592/n log Q

E°cell= 0.48 V

E= 0.48 - 0.0592/6 log (12.5)

E= 0.47V