1 cup= 8 fluid ounces, so therefore 5 cups=40 fluid ounces. Hope this helps! :)
Answer:
- The mean for Group A is less than the mean for Group B.
- The median for Group A is less than the median for Group B.
- The mode for Group A is less than the mode for Group B.
Step-by-step explanation:
First, we can find the measures of center for each group.
<u>Group A</u>
Mode: 1
Median: (1 + 2) / 2 = 3 / 2 = 1.5
Mean: (1 * 5 + 2 * 4 + 3) / 10 = (5 + 8 + 3) / 10 = 16 / 10 = 1.6
<u>Group B</u>
Mode: 3
Median: 92 + 3) / 2 = 5 / 2 = 2.5
Mean: (1 * 3 + 2 * 2 + 3 * 4 + 5) / 10 = (3 + 4 + 12 + 5) / 10 = 24 / 10 = 2.4
From here, we can see that...
- The mean for Group A is less than the mean for Group B.
- The median for Group A is less than the median for Group B.
- The mode for Group A is less than the mode for Group B.
Hope this helps!
18. If f(x)=[xsin πx] {where [x] denotes greatest integer function}, then f(x) is:
since x denotes the greatest integers which could the negative or the positive values, also x has a domain of all real numbers, and has no discontinuous point, then x is continuous in (-1,0).
Answer: B]
20. Given that g(x)=1/(x^2+x-1) and f(x)=1/(x-3), then to evaluate the discontinuous point in g(f(x)) we consider the denominator of g(x) and f(x). g(x) has no discontinuous point while f(x) is continuous at all points but x=3. Hence we shall say that g(f(x)) will also be discontinuous at x=3. Hence the answer is:
C] 3
21. Given that f(x)=[tan² x] where [.] is greatest integer function, from this we can see that tan x is continuous at all points apart from the point 180x+90, where x=0,1,2,3....
This implies that since some points are not continuous, then the limit does not exist.
Answer is:
A]
Answer:
16.75 g
Step-by-step explanation:
Orange's weight = 67 g
Strawberry's weight
= ¼ of the weight of orange
= ¼ × weight of orange
= ¼ × 67 g
= 67 g/4
= 16.75 g
