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MissTica
3 years ago
12

What is diffusion....?​

Chemistry
2 answers:
777dan777 [17]3 years ago
5 0

Answer:

It is the net movement of anything from a region of higher concentration to a region of lower concentration.

Anvisha [2.4K]3 years ago
5 0

Answer:

<em>the movement of individual molecules of a substance through a semipermeable barrier from an area of higher concentration to an area of lower concentration</em><em>.</em>

<em>hope</em><em> </em><em>this helps</em><em> </em><em><</em><em>3</em>

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How many atoms of S are there?
jonny [76]
Atoms of sulfur = 9.60⋅g32.06⋅g⋅mol−1×6.022×1023⋅mol−1 . Because the units all cancel out, the answer is clearly a number, ≅2×1023 as required.
4 0
3 years ago
Read 2 more answers
If the half-life of a radioactive substances is 590 million years and you have 40 atoms of it, how many half-lives will have pas
Nady [450]

Answer:

3

Explanation:

Applying,

2^{n'} = R/R'............... Equation 1

Where n' = number of halflives that have passed, R = Original atom of the substance, R' = atom of the substance left after decay.

From the question,

Given: R = 40 atoms, R' = 5 atoms

Substitute these values into equation 1

2^{n'} = 40/5

2^{n'} = 8

2^{n'} = 2³

Equation the base,

n' = 3

3 0
2 years ago
CH3-CH2-CH=CH-CH=CH2
o-na [289]

Answer:

Hydration (of an alkene)

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8 0
2 years ago
Aluminum and oxygen react according to the following equation: 4Al + 3O2 -&gt; 2Al2O3 In a certain experiment, 4.6g Al was react
stiv31 [10]

Answer:

Percent yield: 78.2%

Explanation:

Based on the reaction:

4Al + 3O₂ → 2Al₂O₃

<em>4 moles of Al produce 2 moles of Al₂O₃</em>

<em />

To find percent yield we need to find theoretical yield (Assuming a yield of 100%) and using:

(Actual yield (6.8g) / Theoretical yield) × 100

Moles of 4.6g of Al (Molar mass: 26.98g/mol) are:

4.6g Al × (1mol / 26.98g) = 0.1705 moles of Al.

As 4 moles of Al produce 2 moles of Al₂O₃, theoretical moles of Al₂O₃ obtained from 0.1705 moles of Al are:

0.17505 moles Al × (2 moles Al₂O₃ / 4 moles Al) = <em>0.0852 moles of Al₂O₃</em>,

In grams (Molar mass Al₂O₃ = 101.96g/mol):

0.0852 moles of Al₂O₃ × (101.96g / mol) =

<h3>8.7g of Al₂O₃ can be produced (Theoretical yield)</h3>

Thus, Percent yield is:

(6.8g / 8.7g) × 100 =

<h3>78.2% </h3>
8 0
3 years ago
Calculate the atomic mass of silicon. The three silicon isotopes have atomic masses and relative abundances of 27.9769 amu (92.2
Kamila [148]
The atomic mass would be 28.08535 amu. Multiply 27.9769 by .92297 = 25.803. Multiply 28.9765 by .046832 to get 1.357. Multiply 29.9738 by .03872 to get .925351136. Add 25.803 + 1.357 + .03872 to get 28.08535 amu
6 0
3 years ago
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