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3 years ago

3.04 Quiz: Chemical Reactions 1 to 10 question

Chemistry

1 answer:

vaieri [72.5K]3 years ago

5 0

Answer:

1. Chemical reactions

2.Substances

3. Properties

4. Precipitate

5. Light

6. Temperature

7. Color

8. Gas

Explanation:

During chemical reactions, new substances that possess new properties are formed. During the process of chemical reactions, evidences are found. Some of the evidences are formation of precipitate or light gel, production of gases and changes in color and temperature.

Chemical reactions start with the substances or compounds which are known as reactants. The reactants react to form new substances known as the products which possess new properties.

I only could help with 1 - 8 sorry.

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Answer: The red blood cell will shrink due to water loss

Explanation:

Because 1% NaCl solution is slightly more concentrated than its isotonic 0.9% form, the red blood cell will lose its cell containing fluids such as water to the MORE concentrated environment.

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Suppose that a certain atom possesses only four distinct energy levels. Assuming that all transitions between levels are possibl

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Answer:

Following are the response to the given question:

Explanation:

The number of shells

n = 4

Calculating the spectral line:

$= \frac{n(n-1)}{2}\\\\ = \frac{4(4-1)}{2} \\\\= \frac{4\times 3}{2}\\\\ = \frac{12}{2}\\\\ = 6$

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2. Hydrogen gas at a temperature of 22.0°C that is confined in a 5.00L cylinder exerts a pressure of 4.20atm. If the gas is rele

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Explanation:

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A mixture of 117.9 g of P and 121.8 g of O, reacts completely to form P4O6 and P4O10. Find the masses of P4O6 and P4O10

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Answer:

Mass of P4O6=103.4

P4O10=133.48

Explanation:

Balanced reaction is:

8P +8 $O_{2}$ ⇒ $P_{4} O_{6}$ + $P_{4} O_{10}$

Both reactant completely vanishes as equivalent of bot are equal.

Moles of P= $\frac{117.9}{31}$ =3.80

Moles of $O_{2}$ = $\frac{117.9}{31}$ =3.80

No. of moles of formed product are equal and is $\frac{1}{8}$ th of mole of any of reactant.

Thus weight of $P_{4} O_{6}$ = $\frac{3.80}{8}$ ×220 ≈103.41

weight of $P_{4} O_{10}$ = $\frac{3.80}{8}$ ×284 ≈133.48

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