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PtichkaEL [24]
3 years ago
7

which are correct formulas for ionic compounds? for those that are not correct, give the correct formula and justify your answer

Chemistry
1 answer:
galina1969 [7]3 years ago
4 0

Answer:

a. AlCl is incorrect because Al has a +3 charge while Cl only has a -1 charge. The correct formula would be AlCl₃. This balances the charges.

b. Na₃SO₄ is incorrect because Na has a charge of +1 and there are three of them so its +3 and SO₄ has a charge of -2. The correct formula would be Na₂SO₄. This balances the charges.

c. BaOH₂ is incorrect because the polyatomic ion OH would not be written that way. It would be written like this Ba(OH)₂. Writing it like BaOH₂ gives the impression that instead of having 2 OH it has 2 H and 1 O.

d. Fe₂O is incorrect because Fe either has a +2 charge or +3 charge while O has a -2 charge. Possible correct answers could be FeO (iron (II) oxide) or Fe₂O₃ (iron (III) oxide).

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Which property decreases when the element in group 17 are considered in order of increasing atomic number
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Electromagnetically decreases when the elements are considered in order of increasing atomic number.
In this problem they were asking regarding group 17.
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The gas in a balloon has a volume of 2 Lat a temperature of 301 K. What will be the final temperature (in K) when the volume exp
Blizzard [7]

Answer:

Final temperature = 1279.25 K

Explanation:

We can solve this using the formula for Charles law since we are given volume and temperature.

From Charles law, we know that;

V1/T1 = V2/T2

Where;

T1 is the initial temperature

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T2 is the final temperature

V2 is the final volume

We are given;

V1 = 2 L

T1 = 301 K

V2 = 8.5 L

Thus, making T2 the subject, we have;

T2 = V2•T1/V1

Plugging in the relevant values;

T2 = 8.5 × 301/2

T2 = 1279.25 K

4 0
3 years ago
How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m
Pie

<u>Answer:</u> The mass of sodium acetate that must be added is 30.23 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of acetic acid solution = 0.200 M

Volume of solution = 1 L

Putting values in above equation, we get:

0.200M=\frac{\text{Moles of acetic acid}}{1L}\\\\\text{Moles of acetic acid}=(0.200mol/L\times 1L)=0.200mol

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{salt}]}{[\text{acid}]})  

pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})

We are given:

pK_a = negative logarithm of acid dissociation constant of acetic acid = 4.74

[CH_3COONa]=?mol  

[CH_3COOH]=0.200mol

pH = 5.00

Putting values in above equation, we get:

5=4.74+\log(\frac{[CH_3COONa]}{0.200})

[CH_3COONa]=0.364mol

To calculate the mass of sodium acetate for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of sodium acetate = 83.06 g/mol

Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g

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