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Sergeu [11.5K]
3 years ago
12

If a stock has a required return of "r", its next dividend is expected to be "DIV1", and its dividends are expected to grow at a

constant rate "g" thereafter, then its current share price "P0" can be determined by __________. P0=DIV1/(r-g) P0=DIV1 x (r-g) P0=P1/r P0=DIV1/r
Mathematics
1 answer:
Kryger [21]3 years ago
5 0

Answer:

The correct formula is P_0=\dfrac{DI V_1}{(r-g)}

Step-by-step explanation:

\text{Current share price}=\frac{\text{Estimated dividend for next month}}{\text{Required rate of return - constant growth rate}}

Here,

Required rate = r,

Growth rate = g,

Estimated dividend for next month = DIV_1

Current share price = P_0

By substituting the values in the above formula,

P_0=\dfrac{DI V_1}{(r-g)}

Hence, the correct formula of current share is,

P_0=\dfrac{DI V_1}{(r-g)}

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-3(3+x)+4(x-6)=-4 Please help me with this question
dsp73

Answer:

\boxed{ \bold{ \huge{ \sf{x = 29}}}}

Step-by-step explanation:

\sf{ - 3(3 + x) + 4(x - 6) =  - 4 }

Distribute -3 through the parentheses

Similarly, Distribute 4 through the parentheses

⇒\sf{ - 9 - 3x + 4x - 24 =  - 4}

Collect like terms

⇒\sf{x - 9 - 24 =  - 4}

Calculate

⇒\sf{x - 33 =  - 4}

Move 33 to right hand side and change it's sign

⇒\sf{x =  -  4 + 33}

Calculate

⇒\sf{x = 29}

Hope I helped!

Best regards!!

7 0
4 years ago
You purchase a cell phone for $125. the value of the cell phone decreases by about 20% annually. write a function at models the
djverab [1.8K]
F(x)=125-(125*0.2x)
to find the value of the phone after 3 years, you put x=3.
f(3)=125-(125*0.2(3))
f(3)=50
5 0
3 years ago
Write an equation of the line y-intercept =-11/2
Vadim26 [7]
To write an equation of a line, you need to also know the slope or have a graph
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3 years ago
The double number line shows that 4 kilograms of almonds cost $34
Nuetrik [128]
34/4=8.5
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2 years ago
Please answer question now
nata0808 [166]

Answer:

469.42 ft²

Step-by-step explanation:

  • Law of sines;

         w/sin27 = 38/sin40

                   w = sin27*38/sin40

                    w = 26.84 ft

  • Angle x;

            ∡X = 180 - 27- 40 = 113º

  • Area;

              A = 0.5*(26.84)*(38)*sin(113)

            A = 469.42 ft²

8 0
3 years ago
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