The final molarity of HCl is 2.284 M
We'll begin by listing what was given from the question. This is shown below:
Initial volume (V₁) = 5.56 mL
Initial Molarity (M₁) = 4.108 M
Final volume (V₂) = 5.56 + 4.44 = 10 mL
<h3>Final Molarity (M₂) =? </h3>
The final molarity of the HCl solution can be obtained by using the dilution formula as illustrated below:
<h3>M₁V₁ = M₂V₂</h3>
4.108 × 5.56 = M₂ × 10
22.84048 = M₂ × 10
Divide both side by 10
M₂ = 22.84048 / 10
<h3>M₂ = 2.284 M</h3>
Therefore, final molarity of the HCl solution is 2.284 M.
Learn more: brainly.com/question/6103588
Answer:
I believe it is "Arsenenate"
First, you need to calculate the standard cell potential using standard reduction potential from a textbook or online. Since Mg becomes Mg+2, magnesium is being oxidized because it is losing electrons, you need to flip its potential
Fe+2 + 2e- --> Fe potential= -0.44
Mg+2 + 2e- --> Mg potential= -2.37
Cell potential= (-0.44) + (+2.37)= 1.93 V
Now, you need to use Nernst formula to get the answer. I have attached a PDF with the work.
Answer:
What is the volume of the balloon when it rises in the atmosphere to a place where pressure is 640mmHg
Answer:
ACE
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