Answer:
The structure for the compound elucidated (4-Ethylbenzoic acid) is attached below.
Explanation:
Degree of Unsaturation =
(where n = no of moles)
=
= 9 - 6+1 = 4
⇒ 2 ring. 3 double bonds.
From the 1H NMR data given (peaks labeled A-E)
A. 1.2 (3H, t) ⇒ -CH3
B. 2.6 (2H, q) ⇒ -C=C-H or Aromatic-CH3
C. 7.3 (2H, d) ⇒ Aro.-H
D. 8.0 (2H, d) ⇒ Aro.-H
E. 11.0 (1H, s) ⇒ -COOH
Molecular geometry about the left carbon atom in CH₃CO₂CH₃ is tetrahedral.
The geometry around left carbon that is CH₃ is tetrahedral.
As the hybridization around left carbon is sp³ that shows its geometry should be tetrahedral and as there are 4 ligands around carbon and there is no lone pair present so the geometry is tetrahedral. So, the molecular geometry about the left carbon atom in CH₃CO₂CH₃ is tetrahedral.
This the balanced equation based on the question

.
We then proceed with the following calculations
The answer is
is produced.
Answer:
14.89 g
Explanation:
Please see the step-by-step solution in the picture attached below.
Hope this answer can help you. Have a nice day!