2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)
65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.
Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)
=0.0282669621 g of O2 left over
potassium belongs to group IA of the periodic table.
Answer: 4 hydrogens
Explanation:
This is what the structure will look like C=C. Remember that it's important that all structures have a complete octet. As it looks right now each carbon is sharing 4 valence electrons so each needs 2 more bonds to hydrogen complete its octet.
The specific heat is 0.401 J/(g x C). The specific heat is the amount of heat of one unit mass of an object required to raise the temperature by one degree Celsius. The specific amount can be calculated using Cp = Q/(m x changes in T) formula, where Cp is the specific heat, Q is the amount of heat, m is the object's mass, and changes in T is the changes in temperature<span>.</span>
