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OverLord2011 [107]
3 years ago
13

Which chemical property deals with the ability of a substance being able to

Chemistry
2 answers:
Fantom [35]3 years ago
5 0

\large\underline{\bf\red{Solution:-}}

The chemical property deals with the ability of a substance being able to burn is called combustibility [ option b ] .

<u>More</u><u> to</u><u> know</u><u> </u><u>:</u><u>-</u>

<em>1</em><em>)</em><em> </em><em>Combustion</em><em> </em><em>:</em><em>-</em>

Combustion is a chemical process in which a substance reacts rapidly with oxygen and gives out heat.

The fuel can be any one of the 3 states of matter that is - solid , liquid & gases .

Examples of combustible substances :-

Solid - Coal

Liquid - Petrol , Disel , etc.

Gas - Hydrogen , Oxygen , etc .

Mandarinka [93]3 years ago
3 0

Answer:

combust

Explanation:

did the test

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A binding protein binds to a ligand L with a Kd of 400 nM. What is the concentration of ligand when Y is (a) 0.25, (b) 0.6, (c)
Mrac [35]

Answer:

(a) 133.33nm

(b) 600nm

(c) 7,600nm

Explanation:

The concentration of Y can be determined by using the formula:

Y = \dfrac{[L]}{k_d+[L]}

where;

[L] = concentration of the binding ligand.

kd = 400 nm

Thus:

When Y = 0.25; we get :

0.25 = \dfrac{[L]}{400+[L]}

0.25 (400 + [L]) = [L]

100 + 0.25[L] = [L]

100 = [L] - 0.25 [L]

100 = 0.75 [L]

[L] = 100/0.75

[L] = 133.33 nm

At, Y = 0.6

0.6 = \dfrac{[L]}{400+[L]}

0.6 (400 + [L]) = [L]

240 + 0.6[L] = [L]

240 = [L] - 0.6 [L]

240 = 0.4 [L]

[L] = 240/0.4

[L] = 600 nm

At, Y = 0.95

0.95 = \dfrac{[L]}{400+[L]}

0.95 (400 + [L]) = [L]

380 + 0.95[L] = [L]

380 = [L] - 0.95 [L]

380 = 0.05 [L]

[L] = 380/0.05

[L] = 7600 nm

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3 years ago
What is the temperature in kelvin of the Xe in the balloon?
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Smaller container means less volume, and the molecules will hit the walls of the container more frequently because there's less space available and the pressure will go up. I guess this would mean that the side with fewer moles would be favored as a result. We count the number of moles on the reactants and products and find that there are fewer moles on the product side, so I guess this would favor the product formation.

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