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Bess [88]
3 years ago
8

The consumption schedule is such that Multiple Choice

Chemistry
1 answer:
Serga [27]3 years ago
8 0

Answer:

a. the MPC is constant and the APC declines as income rises.

Explanation:

Hello,

At first, lets remember that the marginal propensity to consume (MPC) is a indicator that quantifies the induced consumption. It occurs with an increase in disposable income (income after taxes and transfers).

On the other hand, APC is the ratio of consumption to income as well as the proportion of income that is consumed.

In this manner, the consumption schedule is such that the MPC is constant and the APC declines as income rises, that is a. option.

Best regards.

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Gravity and Thermal pressure

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How can you recognize an alcohol?
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Answer:

O D. It has an -OH group attached to the end of the molecule.

Explanation:

Some alcohols have hydroxyl group (OH) attached to the end of a molecule and some have it attached as a branch on the molecule

{ \rm{R - OH \:  : \: primary \: alcohol   \: (1 \degree)}}  \\  \\ { \rm{R -(OH) - R {}^{i}  \:  : secondary \: alcohol \: (2 \degree)}} \\  \\ { \rm{R - R {}^{i} (OH) - R {}^{ii}  \:  : tertiary \: alcohol \: (3 \degree)}}

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5 0
3 years ago
6. Write the ICE chart for the reaction of 32.0 g of sulfur and 71.0 g of chlorine: S8 + 4 Cl24S2Cl2 After completing the chart
Marianna [84]

Answer:

ICE Table Figure

a. 67.37 g S_2Cl_2

b. 35.62 g Cl_2

c. 58.61 gS_2Cl_2

Explanation:

For the <u>ICE table </u>we have to keep in mind that we have 4 moles of Cl_2 and 1 mol of S_8 and the reactives are consumed, so for Cl_2 we will have -4X and for S_8 we will have -X. Follow the same logic we will have -4X for S_2Cl_2.

a. <u>Mass of the product</u>

Molar mass of S_8= 256.52 g/mol

Molar mass of Cl_2=70.9 g/mol

Molar mass of S_2Cl_2=135.03 g/mol

We have to find the limiting reagent in the reaction:

S_8+4Cl_2->4S_2Cl_2

\frac{32}{256.52}=0.124molS_8

\frac{71}{70.9}=1 molCl_2

Divide by the coefficients in the balanced reaction:

\frac{0.124}{1}=0.124mol

\frac{1}{4}=0.25 mol

The limiting reagent would be S_8

Now is posible to calculate the amount of S_2Cl_2 produced:

0.124molS_8\frac{4molS_2Cl_2}{1 molS_8}\frac{135.03gS_2Cl_2}{1 molS_2Cl_2}=67.37gS_2Cl_2

b. <u>Mass  in excess</u>

0.124molS_8\frac{4molCl_2}{1 molS_8}\frac{70.9gCl_2}{1 molCl_2}=35.38gCl_2

Excess\hspace{0.1cm}=\hspace{0.1cm}71gCl_2-35.38gCl_2=35.62 gCl_2

C. <u>87%Yield</u>

67.37gS_2Cl_2\frac{87}{100}=58.61gS_2Cl_2

5 0
4 years ago
Is this reversible? “ it was silver in color at start but it burned brightly and formed a white powder after heating.”
NARA [144]

Hey there!

This is not reversible.

We know that this is a chemical change because heat is released (it burned brightly) and it formed a new substance (white powder).

Chemical changes are usually not reversible.

Since this is a chemical change, then this is not reversible.

Hope this helps!

3 0
3 years ago
Many human activities are increasing the level of the greenhouse gases in the atmosphere.
Contact [7]

Answer:

true because of burning plants such as crops

Explanation:

7 0
3 years ago
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