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SVETLANKA909090 [29]
3 years ago
6

Determine the molality of a solution in which 2.5 grams of glucose C12H22011 are dissolved in 1492grams of water.

Chemistry
1 answer:
Roman55 [17]3 years ago
6 0
The answer is A hope that helps
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The answer to this question
dedylja [7]
The solutions are the following :
12. C
13. A.
7 0
3 years ago
Analyze A scientist tests the hardness of a mineral and finds that it can scratch
zhuklara [117]

Topaz and quartz

Explanation:

Topaz and quartz are minerals that will scratch feldspars but will not scratch corundum. Corundum is one of the hardest substance based on moh's scale.

The hardness of a mineral is its resistance to deformation. A mineral is harder than another if it can scratch it.

The moh's scale of hardness list minerals in the order of their hardness:

  1.             Talc
  2.             Gypsum
  3.             Calcite
  4.             Fluorite
  5.              Apatite
  6.              Orthoclase
  7.              Quartz
  8.              Topaz
  9.               Corundum
  10.               Diamond

Diamond is the hardest and talc is the softest.

Orthoclase is a feldspar.

learn more:

Rocks as mineral aggregates brainly.com/question/6568161

Silicate minerals brainly.com/question/4772323

#learnwithBrainly

8 0
3 years ago
Help please asap. chem sucks
luda_lava [24]

I'm assuming that C is carbon.

4.590 \: mol \: c \times  \frac{12.01 \:g \: c}{1 \: mol \: c}

55.1259 g of C

6 0
3 years ago
The decomposition of hydrogen peroxide, H2O2, has been used to provide thrust in the control jets of various space vehicles. Usi
lesantik [10]

Answer:

\Delta H^0 _{reaction} = - 54.04 \ kJ/mol

Explanation:

The given equation for the chemical reaction can be expressed as;

2H_2O_{(l)}  \to 2H_2O_{(g)} +  O_{2(g)}

Using Hess Law to determine how much heat is produced by the decomposition of exactly 1 mole of H2O2 under standard conditions; we have the expression showing the Hess Law as follows:

\Delta H^0 _{reaction} = \sum n* \Delta H^0 _{products} -  \sum n* \Delta H^0 _{reactants}

At standard conditions;

the molar enthalpies of the given equation are as follows:

\Delta H_2O_{(g)} =-241.82\ kJ/mol

\Delta H_  O_{2(g)} = 0 \ kJ/mol

\Delta H _{H_2O_{(l)}}= -187.78  \ kJ/mol

Replacing them into above formula; we have:

\Delta H^0 _{reaction} = (2*(-241.82\ kJ/mol) + 0 \ kJ/mol + (2 *(-187.78 \ kJ/mol))

\Delta H^0 _{reaction} =-108.08 \ kJ/mol

The above is the amount of heat of formation for two moles of hydrogen peroxide; thus for 1 mole hydrogen peroxide ; we have :

\Delta H^0 _{reaction} = \dfrac{-108.08 \ kJ/mol}{2}

\Delta H^0 _{reaction} = - 54.04 \ kJ/mol

Hence; the heat produced after the decomposition of 1 mole of hydrogen peroxide is -54.04 kJ/mol

6 0
4 years ago
How is hydrogen an example of an element?
pshichka [43]

Answer:

Hydrogen is an example of an element because its displayed on the periodic table of elements

Explanation:

8 0
2 years ago
Read 2 more answers
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