Question

An electrical motor spins at a constant 2695.0 rpm. If the armature radius is 7.165 cm, what is the acceleration of the edge of the rotor?
A) 28.20 m/s^2

B) 572,400 m/s^2

C) 281.6 m/s^2

D) 5707 m/s^2

Answer 1

Answer:

Acceleration will be $5706.77rad/sec^2$

So option (D) will be correct answer

Explanation:

We have given angular speed of the electrical motor $\omega =2695rpm$

We have to change this angular speed in rad/sec for further calculation

So $\omega =2695rpm=2695\times \frac{2\pi }{60}=282.2197rad/sec$

Armature radius is given r = 7.165 cm = 0.07165 m

We have to find the acceleration of edge of motor

Acceleration is given by $a=\omega ^2r=282.2197^2\times 0.07165=5706.77rad/sec^2$

So acceleration will be $5706.77rad/sec^2$

So option (D) will be correct answer