What type of materials do mechanical waves move fastest through?

How can you defend the ball handler in basketball

malfutka [58]

By playing defense and sliding your feet together while standing in front of the ball handler

7 0

3 years ago

If a diver-in-training is put into a pressurized suit, by how much would the pressure have to be raised (in atmospheres) above a

Sever21 [200]

This is an incomplete question, here is a complete question.

The bulk modulus for bone is 15.0 (GPa). If a diver-in-training is put into a pressurized suit, by how much would the pressure have to be raised (in atmospheres) above atmospheric pressure to compress her bones by 0.130% of their original volume?

Answer : The change in pressure will be, $1.95\times 10^7Pa$

Explanation : Given,

Bulk modulus = $15.0GPa=15.0\times 10^9Pa$

Change in volume = 0.130 % of original volume

Let the original volume be, V

So, Change in volume = $\frac{0.130}{100}\times V$

Formula used for change in pressure is:

$\Delta P=\beta \frac{\Delta V}{V}$

Now put all the given values in this formula, we get:

$\Delta P=(15.0\times 10^9Pa)\times \frac{(\frac{0.130}{100}\times V)}{V}$

$\Delta P=1.95\times 10^7Pa$

Thus, the change in pressure will be, $1.95\times 10^7Pa$

8 0

4 years ago

Two of the angles in a triangle are complementary. The third angle is twice the measure of one of the complementary angles. What

Marrrta [24]

Explanation:

Let the 2 be X and Y.

Z is 3rd angle.

Z=2X

w.k.t Sum of angles in a triangle is 180°

Z+X+Y=180°

2X+90°=180°

2X=90°

=>X=45°

=>Y=90°-45°=45°

=>Z=2X=2(45°)=90°

Hope this helps you.

6 0

3 years ago

Un recipiente con una capacidad de 25L contiene un gas a una presión de 7,5 atm. Calcula la nueva presión a la que se verá somet

amid [387]

Responder:

18.75 atmósferas

Explicación:

Paso uno:

datos dados

volumen inicial V1 = 25L

Presión inicial P1 = 7.5 atm

volumen final V2 = 10L

presión final P2 = ??

Segundo paso:

Aplicando la expresión de gas que relaciona el volumen y la presión, es decir

P1V1 = P2V2

sustituyendo nuestros datos tenemos

7.5 * 25 = P2 * 10

187.5 = P2 * 10

divide ambos lados por 10

P2 = 187.5 / 10

P2 = 18.75 atmósferas

<em><u>La presión final es de 18.75 atm.</u></em>

5 0

3 years ago

A firework is designed so that when it is fired directly upwards, it explodes and splits into three equal-massed parts at its pe

Arturiano [62]

Answer:

the third piece landed $2\,\sqrt{2}$ meters in a direction 45 degrees from the observer's right towards the front

Explanation:

Due to conservation of momentum, the momentum of the third piece must add to the other two momenta in vector from to render zero (initial momentum of the firework on a plane parallel to ground. Therefore the momentum components of the third piece must have a component to the right equal in magnitude to the momentum of the piece that traveled to the left, and a momentum component pointing to the front of the observer of equal magnitude to that of the piece that traveled behind the observer. Then the direction of the third momentum must be at 45 degrees from the observer's right towards the observer's front.

Also, the magnitude of a momentum vector of such components, is given by the Pythagorean theorem. Recall also that the magnitudes of the momentum vectors of the first two pieces must be equal since they traveled equal distances.

$|P_3|=\sqrt{P_1^2+P_2^2} \\|P_3|=\sqrt{P^2+P^2}\\|P_3|=\sqrt{2P^2}\\|P_3|=P\sqrt{2}$

Then the distance traveled by the third piece must also keep this proportionality:

$D_3=\sqrt{2} \,\,D\\D_3=\sqrt{2} \,*\,2\,\,meters\\D_3=2\,\sqrt{2} \,\,meters$

4 0

3 years ago