Answer:
a)
b) m/s
c) = 1.952 kg.m/s
Explanation:
Given:
Mass of the skateboard, = 1.5 kg
Combined mass, = 105 kg
velocity of the book, = 2.97 m/s
angle, θ = 26°
thus,
horizontal component of the velocity = vcosθ
vertical component of velocity = vsinθ
a) Applying the concept of conservation of momentum
where,
is the velocity of the the student
thus,
............(1)
b) on substituting the values, in the equation we get the magnitude
or
m/s
c) Now, the momentum (P) transferred is given as:
P = mass × velocity
on substituting the values, we get
= mass × velocity
or
=
on substituting the values, we get
=
or
= 1.952 kg.m/s