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drek231 [11]
3 years ago
15

4. You are walking at a leisurely pace of .75 m/s when you hear the train coming and start running to catch it. Over the next 10

seconds, you speed up to 3.5 m/s and catch your train! What was your acceleration over that time?
Physics
1 answer:
hjlf3 years ago
5 0

Answer:

0.275 m/s²

Explanation:

The acceleration of an object is defined as the change in velocity over the change in time.

  • a = Δv/Δt
  • a = (v - v₀)/t

We are given the initial velocity, 0.75 m/s. The final velocity of the user in question is 3.5 m/s.

The time it takes for us to catch the train is 10 seconds. Using these variables, let's substitute into our equation.

  • a = (3.5 - 0.75)/10
  • a = 2.75/10
  • a = 0.275 m/s²

Our acceleration over that time was 0.275 m/s² in order to catch the train.

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3 years ago
A large piece of jewelry has a mass of 130.8 g. A graduated cylinder initially contains 47.7 mL water. When the jewelry is subme
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Explanation:

To calculate the density, we use the equation:

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Density of piece of jewellery = ?

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Putting values in above equation, we get:

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A car is traveling at 10 m/s. 10 seconds later the car is traveling 40 m/s. What is the car’s acceleration?
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Answer:

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