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muminat
3 years ago
10

El ancho de la uña de su dedo meñique se acerca a una unidad metrica comun ¿cual?

Physics
1 answer:
BartSMP [9]3 years ago
3 0

Answer:

I have no clue what's really going on I'm just here to get answer maybe I will just try to get an answer but I have no clue I'm sorry I am confused and dint really know what to do here.

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While studying bacterial cells, scientists measure the lengths of the cells in one colony. The chart shows their data. The scien
jok3333 [9.3K]

Answer:

Following are the solution to the given question:

Explanation:

Its best approach to this measurement ought to be to indicate that there was a mistake throughout the calculation, as well as the gathering of further details while researching cells for bacteria, directly measuring the cell length of a colony. This chart illustrates its data, which scientists have observed that there's still a measurement.

5 0
2 years ago
A 1.40-kg ball tied to a string fixed to the ceiling is pulled to one side by a force F→ . where L = 1.40 kg. What is the tensio
riadik2000 [5.3K]

Answer:

T=13.72N

Explanation:

The tension before the ball is released have no angle is in rest at the same axis of the weight so:

∑F=0

Using Newton law in this case the ball is tied so tension before become to swing is

∑F=FN-T=0

T=F_{N}

T=m*g

T=1.40Kg*9.8\frac{m}{s^2}

T=13.72N

8 0
3 years ago
8. How did the measured angular magnification of the telescope compare with the theoretical prediction?
Genrish500 [490]

Complete Question

The complete question is shown on the first uploaded image  

Answer:

The theoretical angular magnification lies within the angular magnification range

Explanation:

From the question we are told that

   The  focal length of  B  is  f_{objective } =  43.0 \ cm

    The focal length of  A  is   f_{eye} =  10.4 \  cm

The  theoretical angular  magnification is mathematically represented as

           m = \frac{f_{objective }}{f_{eye}}  =  \frac{43.0}{10.4}

            m = \frac{f_{objective }}{f_{eye}}  =  4.175

Form the question the measured angular magnification ranges from 4 -5

So from the value calculated and the value given we can deduce that the theoretical angular  magnification lies within the angular magnification range

3 0
3 years ago
A pilot can withstand an acceleration of up to 9g, which is about 88 m/s2, before blacking out. What is the acceleration experie
Harman [31]

Answer:

Explanation:

Given that, the pilot can withstand 9g acceleration which is approximately 88m/s².

Now, the pilot is traveling in a circle of radius

r = 3340 m

And the speed is

v = 495 m/s

Then, acceleration?

The acceleration of a circular motion can be determine using centripetal acceleration

a = v² / r

a = 495² / 3340

a = 73.36 m/s².

Since the acceleration is less that the acceleration the pilot can withstand, then, I think the pilot makes the turn without blacking out and successfully

4 0
3 years ago
How does the location of the outer planets explain their composition and characteristics?
Elena-2011 [213]

Jupiter, Saturn, Uranus and Neptune collectively make up the group known as the jovian planets. The general structures of the jovian planets are opposite those of the terrestrial planets. Rather than having thin atmospheres around relatively large rocky bodies, the jovian planets have relatively small, dense cores surrounded by massive layers of gas. Made almost entirely of hydrogen and helium, these planets do not have solid surfaces.

6 0
3 years ago
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