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vovikov84 [41]
2 years ago
8

A loop rests in the plane of a page of textbook while a magnetic field is directed into the page. A clockwise current is induced

.
Physics
1 answer:
weqwewe [10]2 years ago
7 0

(b) when the magnetic field gets stronger.

correct option :

When a loop rest in the plane of the page and magnetic field is directed into the page then we will apply here right hand thumb rule in which thumb represent the direction of magnetic field and curling fingers represent direction of induced current. So, in this case the direction of magnetic field is into the page and curling fingers shows induced current in clockwise direction.

  Thus, option (b) is correct.

Incorrect options:

   option (A) is incorrect because when magnetic field will change  

     according to flux.

   option (C) is incorrect because field is stronger so it does not matter

     size of loop increases or decreases.

   option (D) is incorrect because it moves any other side the field will be

     stronger.

Learn more about magnetic field induction here:

 brainly.com/question/13610297

   #SPJ4

[Your question is incomplete, but most probably your full question was-Check all that apply:

A. when the magnetic field is tilted so it is no longer perpendicular to the page

B. when the magnetic field gets stronger

C. when the size of the loop decreases

D. when the loop is moved sideways across the page]

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Assuming the incline to be frictionless and the zero of gravitational potential energy to be at the elevation of the horizontal
Leya [2.2K]

The energy in the system is given by the law of conservation of energy.

The energy stored in the spring plus the gravitational potential energy of the block when it has fully compressed the spring will be equal to m·g·h.

Reason:

The given parameters are;

Surface of the inclined plane = Frictionless

Potential energy at the horizontal line = Zero of gravitational potential

By the law of Conservation of Energy, we have;

The spring will be compressed by a distance, <em>x</em>

The energy stored in the compressed spring, K.E. = (1/2)·k·x²

Energy in the block when the block comes to rest at a height, h₁, will be, P.E. = m·g·h₁

Therefore, by conservation of energy, we have;

The initial potential of the block = The stored energy in the compressed string + The gravitational potential energy of the block when it has compressed.

Therefore, the correct option is; <u>The energy stored in the spring plus the gravitational potential energy of the block when it has fully compressed the spring will be equal to m·g·h</u>

Learn more here;

brainly.com/question/17713698

4 0
2 years ago
Which statement correctly describes these electric field lines?
Otrada [13]
I don’t know, which statement ahh I see white screen lol
4 0
3 years ago
What is the internal energy of 4.50 mol of N2 gas at 253°C? To solve this
Finger [1]

The internal energy of the gas is 49,200 J

Explanation:

The internal energy of a diatomic gas, such as N_2, is given by

U=\frac{5}{2}nRT

where

n is the number of moles

R is the gas constant

T is the absolute temperature of the gas

For the gas in this problem, we have:

n = 4.50 (number of moles)

R = 8.31 J/(mol·K) (gas constant)

T=253^{\circ} + 273 = 526 K (absolute temperature)

Substituting, we find:

U=\frac{5}{2}(4.50)(8.31)(526)=49,200 J

Learn more about ideal gases:

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#LearnwithBrainly

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Vlad1618 [11]
Increase the change in momentum of the collision
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What is the value of acceleration due to gravity at the pole, equator and the centre of the earth
fgiga [73]

Answer:

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