Answer:
a = 0 m/s²
Explanation:
given,
car moving at steady velocity = 100 Km/h
1 km/h = 0.278 m/s
100 Km/h = 27.8 m/s
time of acceleration = 100 s
acceleration is equal to change in velocity per unit time.

change in velocity of the car is 27.8 - 27.8 = 0

a = 0 m/s²
If the car is moving with steady velocity then acceleration of the car is zero.
Hence, the acceleration of the car is equal to a = 0 m/s²
An equilibruium is not changed by a changed in pressure. the answer is false
Now I can actually edit my answer directly: I'm fairly sure I've got this wrong, and my mind has gone blank for how to do it, if someone could delete this that would be great and I'll think about it and see if I can figure it out!
Answer:
Please find the answer in the explanation
Explanation:
When you calculate the SLOPE of a line segment, what does the SLOPE represent? (Choose all that apply) the Distance traveled the Displacement the Velocity the Acceleration None of the above
The slope of any time graph can not give you distance or displacement except for position - time graph.
When you plot either distance or displacement against time, that is, distance time graph or displacement time graph, you can get speed or velocity as the slope of the line segment.
You can only acceleration as a slope in a line of best fit if velocity is plotted against time. That is, in a velocity time graph.