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adoni [48]
3 years ago
7

Write the quadratic equation whose roots are -1 and -5 , and whose leading coefficient is 2 . (Use the letter to represent the v

ariable.)
Mathematics
1 answer:
geniusboy [140]3 years ago
3 0

Answer:

2x^2+12x+10=0

Step-by-step explanation:

When you have the roots r1, r2 and the leading coefficient a of a quadratic equation, its factorization is

a(x - r1)(x - r2)

and the quadratic equation would be

a(x - r1)(x - r2) = 0

In this case r1 = -1, r2 = -5 and a = 2, so the quadratic equation is

\large 2(x-(-1))(x-(-5))=0\Rightarrow 2(x+1)(x+5)=0\Rightarrow\\\\\Rightarrow2(x^2+5x+x+5)=0\Rightarrow2(x^2+6x+5)=0\Rightarrow\\\\\boxed{2x^2+12x+10=0}

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F = uv/u + v make u the subject
never [62]

I'm assuming that you mean

\dfrac{uv}{u+v}

because if you meant

\dfrac{uv}{u}+v

then u would simplify and you couldn't make it the subject.

Under this assumption, we start with

F=\dfrac{uv}{u+v}

We multiply both sides by u+v

F(u+v)=uv

We expand the left hand side:

Fu+Fv=uv

We move all terms involving u to the left and all terms not involving u to the right:

Fu-uv=-Fv

We factor u on the left hand side:

u(F-v)=-Fv

We divide both sides by F-v

u=\dfrac{-Fv}{F-v}

3 0
3 years ago
Simplify: x + x + x + x + x + 2x *
Yuki888 [10]

Answer:

7x

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
2ab + a^3 +5a^2b^2 - 2b^3<br> Need help i have to write this in standard form
german
2ab + a^3 + 5a^2b^2 - 2b^3
= a^3 - 2b^3 + 2ab + 5a^2b^2 (this is the expression in standard form)
4 0
3 years ago
Read 2 more answers
I Need help. Thanks.
PIT_PIT [208]

Answer:

A

Step-by-step explanation:

-2(5y-5)-3y\leq -7y+22

Expand parentheses:

-10y+10-3y\leq -7y+22

Move all y's to one side and numbers to the other:

-6y\leq 12

Divide both sides by -6. Since you are dividing both sides by a negative number, you need to flip the comparator:

y\geq -2

Hope this helps!

5 0
3 years ago
Read 2 more answers
Really need help on my correction if anyone know please help!!
Olin [163]
Answers: 
<u>Question 19:</u> 177 bpm
<u>Question 20:</u> 95˚F

Explanations:
<u>Question 19:</u>
You had the formula set up properly like this:
R =  \frac{885 \sqrt{25} }{25}  =  \frac{885(5)}{25}  =  \frac{4425}{25} 
This is where you went wrong - I don't know exactly what you did, but your division of 4425 ÷ 25 is wrong. You should have ended up with 177 which is the correct answer. 
<u>Question 20:</u>
You had the formula set up correctly again, and merely used the wrong sign when adding 32. 
F =  \frac{9(35)}{5} + 32 =  \frac{315}{5} + 32
This is where you went wrong. You subtracted 32 from 63 when you should have added it. (See red circle on your subtraction.)
63 + 32 = 95˚F
7 0
3 years ago
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