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3 years ago

What is the complete factorization of x^2+4x-45?

Mathematics

2 answers:

erma4kov [3.2K]3 years ago

5 0

Answer:(x-5)(x+9)

Step-by-step explanation:

You want two numbers that can give you -45 in multiplication and two numbers that can add to 4 and that is -5 and 9.

Otrada [13]3 years ago

4 0

Answer: (x - 5)(x + 9)

If you have to solve, x=5 or x= -9

Step-by-step explanation: You need two numbers that multiply to be 45.

(could be 3 × 15 or 5 × 9) . The difference between the two factors needs to be 4, the coefficient of the middle term.

9 - 5 =4, so use those. -45 has a negative sign, so one of the factors must be + and the other - Since the 4 has the + sign, the larger factor has to be + so the difference will be positive.

So (x -5)(x + 9) are your factors. You can FOIL to be sure

x × x += x² . x × 9 = 9x . -5 × x = -5x . -5 × 9 = -45 .

Combine the x terms: 9x -5x = +4x

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3 years ago

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Answer:

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3 years ago

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2 years ago

Given that tan^2 theta=3/8,what is the value of sec theta?

algol [13]

Answer:

The value of SecФ is $\pm \sqrt{\frac{11}{8}}$ .

Step-by-step explanation:

Given as for trigonometric function :

tan²Ф = $\frac{3}{8}$

Or, tanФ = $\sqrt{\frac{3}{8} }$

∵ tanФ = $\frac{Perpendicular}{Base}$

So, $\frac{Perpendicular}{Base}$ = $\sqrt{\frac{3}{8} }$

So, Hypotenuse² = perpendicular² + base²

or, Hypotenuse² = ( $\sqrt{3}$ )² + ( $\sqrt{8}$ )²

Or, Hypotenuse² = 3 + 8 = 11

Or, Hypotenuse = ( $\sqrt{11}$ )

Now SecФ = $\frac{Hypotenuse}{Base}$

or, SecФ = $\frac{\sqrt{11}}{\sqrt{8}}$ = $\sqrt{\frac{11}{8} }$

<u>Second Method</u>

Sec²Ф - tan²Ф = 1

Or, Sec²Ф = 1 + tan²Ф

or, Sec²Ф = 1 + $\frac{3}{8}$

Or, Sec²Ф = $\frac{11}{8}$

Or, SecФ = $\pm \sqrt{\frac{11}{8}}$

Hence The value of SecФ is $\pm \sqrt{\frac{11}{8}}$ . Answer

7 0

3 years ago

Read 2 more answers

What is the complete factorization of x^2+4x-45?​

What is the complete factorization of x^2+4x-45?