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Vitek1552 [10]
3 years ago
14

What is the complete factorization of x^2+4x-45?​

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
5 0

Answer:(x-5)(x+9)

Step-by-step explanation:

You want two numbers that can give you -45 in multiplication and two numbers that can add to 4 and that is -5 and 9.

Otrada [13]3 years ago
4 0

Answer:  (x - 5)(x + 9)

If you have to solve, x=5 or x= -9

Step-by-step explanation: You need two numbers that multiply to be 45.

(could be 3 × 15 or 5 × 9) . The difference between the two factors needs to be 4, the coefficient of the middle term.

9 - 5 =4, so use those.  -45 has a negative sign, so one of the factors must be + and the other -  Since the 4 has the + sign, the larger factor has to be + so the difference will be positive.

So (x -5)(x + 9) are your factors. You can FOIL to be sure

x × x += x² . x × 9 = 9x .  -5 ×  x = -5x . -5 × 9 = -45 .

Combine the x terms: 9x -5x = +4x  

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There's not enough information to figure out the grasshoppers, but there should be 15 lady bugs, because 5+10=15
8 0
3 years ago
Identify the period for the trigonometric function: f (t) = −2sec(t).
Agata [3.3K]

Answer:

The answer is 2pi.

Hope this helps you. Also if you practice your material better you won't need to ask. Studying is the medicine to all problems xD



3 0
3 years ago
15 points Help asap thanks so much
lyudmila [28]
The answer is inconsistent
5 0
3 years ago
1. The graph of y = x2 is translated 4 units down and 3 units to the left. It is also stretched by a factor
slega [8]

Answer:

ok so first ur gonna do 4x3=12 then

Step-by-step explanation:

7 0
2 years ago
Given that tan^2 theta=3/8,what is the value of sec theta?
algol [13]

Answer:

The value of SecФ is  \pm \sqrt{\frac{11}{8}} .

Step-by-step explanation:

Given as for trigonometric function :

tan²Ф = \frac{3}{8}

Or, tanФ = \sqrt{\frac{3}{8} }

∵ tanФ = \frac{Perpendicular}{Base}

So,  \frac{Perpendicular}{Base} =  \sqrt{\frac{3}{8} }

So, Hypotenuse² = perpendicular² + base²

or, Hypotenuse² = ( \sqrt{3} )² + ( \sqrt{8} )²

Or,  Hypotenuse² = 3 + 8 = 11

Or,  Hypotenuse = ( \sqrt{11} )

Now SecФ = \frac{Hypotenuse}{Base}

or, SecФ = \frac{\sqrt{11}}{\sqrt{8}} = \sqrt{\frac{11}{8} }

<u>Second Method</u>

Sec²Ф - tan²Ф = 1

Or, Sec²Ф = 1 +  tan²Ф

or, Sec²Ф = 1 +  \frac{3}{8}

Or, Sec²Ф = \frac{11}{8}

Or,  SecФ = \pm \sqrt{\frac{11}{8}}

Hence The value of SecФ is  \pm \sqrt{\frac{11}{8}} . Answer

7 0
3 years ago
Read 2 more answers
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