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3 years ago

Question 4(HELP ASAP)

1 answer:

5 0

The pressure decreases when the volume is increased given at the constant temperature. Thereby, here in the question, based upon the relationship, the $P_{1} V_{1}=P_{2} V_{2}$ .

Answer: option A

<u>Explanation:</u>

According to the Boyle’s law, the pressure and volume are in inverse proportional ratio for their relationship to understand, when the temperature is kept constant at all times for establishing the relationship.

Therefore, as given, pressure decreases from 4 atm to 0.2 atm, which itself shows the decrease, while the volume has increased to 500 L, which must be initially 25 L. According to the equation of Boyle’s law,

$P_{1} V_{1}=P_{2} V_{2}$

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4 years ago

Serving at a speed of 170 km/h, a tennis player hits the ball at a height of 2.5 m and an angle θ below the horizontal. the base

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serving speed = 170 km/h

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also in x and y directions we know

$2.5 - 0.91 = v_y*t + \frac{1}{2}gt^2$

$11.9 = v_x *t$

$1.59 = v_y*t + 4.9*t^2$

$1.59 = 11.9 tan\theta + 4.9*(\frac{11.9}{47.22})^2(1 + tan^2\theta)$

$1.59 = 11.9 tan\theta + 0.311 (1 + tan^2\theta)$

by solving above equation we have

$tan\theta = 0.107$

$\theta = 6.11 degree$

so angle is 6.11 degree below the horizontal

now we have

$v_y = 47.22 sin6.11 = 5.02 m/s$

$v_x = 47.22 cos6.11 = 46.95 m/s$

now time taken by ball to reach the ground will be

$2.5 = 5.02 * t + \frac{1}{2}gt^2$

$t = 0.37 s$

now the displacement in x direction will be

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Complete Question:

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Explanation:

The attached file gives a breakdown step by step solution to the questions

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