3 years ago

Parking orbit is defined accurately by (a) 1" Kepler's law (b) 2 Kepler's law (c) 2 and 3 Kepler's law (d) 3" Kepler's law

Physics

1 answer:

ehidna [41]3 years ago

7 0

Answer:

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Explanation:

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Boyle’s Law states that when a sample of gas is compressed at a constant temperature, the pressure P of the gas is inversely pro

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a) $V=\dfrac{5.3}{P}$

b) $ML^{-4}T^{-2}$ .

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Given that

Boyle's law

P V = Constant ,at constant temperature

Given that

$P_1=50KPa$

$V_1=0.106m^3$

We know that for PV=C

$P_1V_1=P_2V_2=PV$

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PV= 50 x 0.106

$V=\dfrac{5.3}{P}$

Where P is in KPa and V is in $m^3$

PV= C

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So $\ln(PV)=\ln C$

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By differentiating

$\dfrac{dP}{P}+\dfrac{dV}{V}=0$

$\dfrac{dP}{dV}=-\dfrac{P}{V}$

When P= 50 KPa

$\dfrac{dP}{dV}=-\dfrac{50}{V}\ \dfrac{KPa}{m^3}$

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3 years ago

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What is the total amount of force needed to keep a 6.0 kg object moving at speed

DanielleElmas [232]

Answer:

C. 0 N

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In the absence of external forces, a body in motion will stay in motion.

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F = 6.0(0) = 0

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3 years ago

Read 2 more answers

Parking orbit is defined accurately by (a) 1" Kepler's law (b) 2 Kepler's law (c) 2 and 3 Kepler's law (d) 3" Kepler's law​

Parking orbit is defined accurately by (a) 1" Kepler's law (b) 2 Kepler's law (c) 2 and 3 Kepler's law (d) 3" Kepler's law