Answer:
Step-by-step explanation:
The sequence above is a geometric sequence.
The common ratio (r) = 
The common ratio < 1, therefore, the formula for the sum of nth terms of the sequence would be: 
a1 = 3
r = -2
n = 6
Plug in the values into the formula
If we begin with the first term, 2, mult. it by 4 and then subtract 3, we get 5 (not 4, as shown).
If we begin with 4, mult. it by 4 and then subtract 3, we get 13. This agrees with the terms of the given sequence.
If we begin with 13, mult. it by 4 and then subtract 3, we get 49. This agrees with the terms of the given sequence.
Remove the first term, 2, and then the remaining terms follow the given procedure for finding terms.
Answer:
First Integer = n = 45
Second Integer = n+1 = 45 + 1 = 46
And Third Integer = n+ 2 = 45 +2 = 47
Step-by-step explanation:
Let First integer = n
Second Integer = n+1
Third Integer = n+2
According to the question given (If the first of three consecutive integers is subtracted from 138, the result is the sum of the second and third) the equation will be:
138 - n = (n+1) + (n+2)
Solving the equation:
138 - n = n+1+n+2
138 - n = 2n+3
138 - 3 =2n +n
135 = 3n
135/3 = n
=> n= 45
So, First Integer = n = 45
Second Integer = n+1 = 45 + 1 = 46
And Third Integer = n+ 2 = 45 +2 = 47
Take 4 and multiply it by 5 (which you should be able to do in your head) and then add the two zeros back in so:
4•5= 20
20+0+0=
2000
Answer:
Let x = the number of adult tickets sold
Let x + 61 = the number of student tickets sold
x + x + 61 = 761
2x = 700
x = 350
x + 61 = 411
