A water bed is 2.00m on a side and 30.0cm deep. Find the pressure that the water bed exerts on the floor. Assume that the entire lower surface of the bed makes contact with the floor.
Density of water, ρ=1000kg/m^3 g=10m/s
This is the missing part of the question.
Answer:
102343.75 Pa
Explanation:
Lenght of bed = 2 m on each side
Depth = 30 cm = 0.3 m
Volume of bed = 2 x 2 x 0.3 = 1.2 m^3
Weight of the bed = pgv
Where p = density of water
g is acceleration due to gravity 10 m/s^2.
V is the volume
Weight of bed = 1000 x 10 x 1.2 = 12000 N
Mass of bed frame = 110 kg
Weight of bed frame = 110 x 10 = 1100 N
Total weight of bed frame and bed = 12000 + 1100 = 13100 N
Side lenght of bed leg = 7 in = 0.1778 m
Area of each bed frame leg = 0.1778 x 0.1778 = 0.032 m2 (legs are square faced)
Total surface area = 0.032. X 4 = 0.128 m2.
Pressure exerted on floor = total weight ÷ area
= 13100/0.128
= 102343.75 Pa
