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lions [1.4K]
3 years ago
15

If you travel at 3 m/s for 12 seconds, how far did you travel?

Physics
2 answers:
Rom4ik [11]3 years ago
8 0

Answer:

\boxed {\tt 36 \ meters }

Explanation:

We want to find how far was traveled, or the <u>distance.</u>

The formula for distance is:

d=s*t

where s is the speed and t is the time.

The speed is 3 meters per second and the time is 12 seconds.

s= 3 \ m/s \\t= 12 \ s

Substitute the values into the formula.

d= 3 \ m/s * 12 \ s

Multiply. Note that when multiply, the seconds, or s will cancel.

d= 3 \ m * 12

d= 36 \ m

d= 36 \ meters

The distance traveled was 36 meters.

ella [17]3 years ago
4 0

Answer:

V=3 m/s

t=12 seconds

S=?

S=V×t

S=3×12

S=36meters

So distance you travel is 36meters.

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What is the maximum speed when the conditions are mass =450 kg, initial height= 30 m, and the roller coaster is initially at res
Zarrin [17]

Answer:

B. 24.2 m/s

Explanation:

Given;

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height of the roller coaster, h = 30 m

The maximum potential energy of the roller coaster  due to its height is given by;

P.E_{max} = mgh\\\\PE_{max} = 450 *9.8*30\\\\PE_{max} = 132,300 \ J

P.E_{max} = K.E_{max} \ (law \ of \ conservation\ of \ energy)

K.E_{max} = \frac{1}{2}mv_{max}^2\\\\ v_{max}^2 = \frac{2K.E_{max}}{m}\\\\ v_{max}^2 = \frac{2*132300}{450}\\\\ v_{max}^2 =588\\\\v_{max} = \sqrt{588}\\\\  v_{max} = 24.2 \ m/s

Therefore, the maximum speed of the roller coaster is 24.2 m/s.

3 0
2 years ago
A white dwarf star has a density of about 1.0 x 10^9 kg/m3. If the earth were to suddenly become as dense as a white dwarf star,
GalinKa [24]

Answer:

R = 98304.75 m = 98.3 km

Explanation:

The density of an object is given as the ratio between the mass of that object and the volume occupied by that object.

Density = Mass/Volume

Now, it is given that the density of Earth has become:

Density = 1 x 10⁹ kg/m³

Mass = Mass of Earth (Constant) = 5.97 x 10²⁴ kg

Volume = 4/3πR³ (Volume of Sphere)

R = Radius of Earth = ?

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1 x 10⁹ kg/m³ = (5.97 x 10²⁴ kg)/[4/3πR³]

4/3πR³ = (5.97 x 10²⁴ kg)/(1 x 10⁹ kg/m³)

R³ = (3/4)(5.97 x 10¹⁵ m³)/π

R = ∛[0.95 x 10¹⁵ m³]

<u>R = 98304.75 m = 98.3 km</u>

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2 years ago
How does the sun’s gravitational attraction impact Earth’s motion?
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Two children ride side-by-side on a carousel. Their paths are shown in the image below.
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The child represented by a star on the outside path.

Explanation:

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