All categories

2 years ago

If you travel at 3 m/s for 12 seconds, how far did you travel?

Physics

2 answers:

Rom4ik [11]2 years ago

8 0

Answer:

$\boxed {\tt 36 \ meters }$

Explanation:

We want to find how far was traveled, or the <u>distance.</u>

The formula for distance is:

$d=s*t$

where $s$ is the speed and $t$ is the time.

The speed is 3 meters per second and the time is 12 seconds.

$s= 3 \ m/s \\t= 12 \ s$

Substitute the values into the formula.

$d= 3 \ m/s * 12 \ s$

Multiply. Note that when multiply, the seconds, or $s$ will cancel.

$d= 3 \ m * 12$

$d= 36 \ m$

$d= 36 \ meters$

The distance traveled was 36 meters.

ella [17]2 years ago

4 0

Answer:

V=3 m/s

t=12 seconds

S=?

S=V×t

S=3×12

S=36meters

So distance you travel is 36meters.

You might be interested in

Mr Ndlovu works in centurion and works at Rosebank.It takes him 13minutes to get to work and he needs to be there at 08h15

VARVARA [1.3K]

Answer:

8:02 no less

Explanation:

8:15 - 13mins = 8:02

6 0

2 years ago

We cannot see a new moon in our sky because ________. We cannot see a new moon in our sky because ________. a new moon is quite

olasank [31]

Answer:

a new moon is quite near the Sun in the sky

Explanation:

7 0

3 years ago

A mountain climber weighs 42.0 N. If he climbs a hill 100m high. Calculate the work done in joules

quester [9]

Answer:

The answer is 4200 J.

Explanation:

The formula of work done is, W = F×D where F is the force of an object and D is the distance. Then you just substitute the values into the equation :

W = F×D

F = 42N

D = 100m

W = 42 × 100

= 4200 J

5 0

2 years ago

Hurryyyyyyyy

padilas [110]

The answer would be C. Gamma Rays and High Frequency EM waves travel at the speed of light and are transverse waves.

7 0

3 years ago

Read 2 more answers

Kelli weighs 425 N, and she is sitting on a playground swing that hangs 0.36 m above the ground. Her mom pulls the swing back an

kodGreya [7K]

Answer:

V = 3.54 m/s

Explanation:

Using the conservation of energy:

$E_i = E_f$

so:

$wh = \frac{1}{2}mV^2$

where w is te weigh of kelly, h the distance that kelly decends, m is the mass of kelly and V the velocity in the lowest position.

So, the mass of kelly is:

m = 425N/9.8 = 43.36 Kg

and h is:

h = 1m-0.36m =0.64m

then, replacing values, we get:

$(425N)(0.64m) = \frac{1}{2}(43.36kg)v^2$

Solving for v:

V = 3.54 m/s

7 0

3 years ago