Answer:
4.16 L
Explanation:
Assuming constant temperature,
At the edge of Typhoon Odessa: P₁ = 1 atm = 1013.3 mbar,
V₁ = 4.0 L
At the center of Typhoon Odessa: P₂ = (1013.3 - 40.0) mbar = 973.3 mbar
V₂ = ? L
For a fixed amount of gas at constant temperature (Boyle's law) : P₁V₁ = P₂V₂
V₂ = V₁ × (P₁/P₂)
V₂= (4.0) × (1013.3/973.3)
V₂= 4.16 L
The ratio of their amplitudes will be 2.41.
To find the answer, we have to know more about the simple harmonic motion.
<h3>How to find the ratio of their amplitudes?</h3>
- We have the relation between these quantities and amplitudes as,
- Here, for both the oscillation, k will be same.
- Thus, the ratio of amplitude will be,
Thus, we can conclude that, the ratio of their amplitudes will be 2.41.
Learn more about simple harmonic motion here:
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Answer:
Explanation:
a )
Pressure on the bottom
= hdg
= 2.5 x 820 x 9.8
= 20090 N / m²
b )
force = area x pressure
= 20090 x 10 x 6 N
= 1205400 N
c )
Force on 10m x 2.5 m face
center of gravity of the tank will lie at height 2 .5 / 2 = 1.25 m
Pressure = hdg
= 1.25 x 820 x 9.8
= 10045 N/m²
force = pressure x area
= 10045 x 10 x 2.5
= 251125 N .
Answer:
7.2 kilowatts
Explanation:
Energy= power x time
where:
power = 1,200watts to kilowatts is 1.2kw
time = 6hours
therefore,
energy = 1.2kw x 6hrs
=7.2 kilowatts
