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saul85 [17]
3 years ago
13

Two cars are sitting still. Car A has a mass of 2000 kilograms. Car B has a mass of 4000 kg. If the goal is to push both cars to

roll at the same speed, describe the force it will take to get Car B to that speed? (Assume everything else is equal: friction & steepness of the road, time, person pushing, etc.)
Physics
1 answer:
astra-53 [7]3 years ago
7 0
Since car B has twice as much mass as car A has, it would require 2x as much force that it would need to push car A down.

If that was kinda confusing lemme say it again,

It would take twice as much that would be needed to push car B down than car A

Since everything is the same, basically two people would need to push down car B and one person for car A

Hope this helps
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Solar collectors are parts of ______. a. passive solar heating systems b. active solar heating systems c. internal combustion en
Bad White [126]

Answer:

b. active solar heating systems

Explanation:

A solar collector is a device that collects and/or concentrates solar radiation from the Sun. These devices are primarily used for active solar heating and allow for the heating of water for personal use.

5 0
3 years ago
The diameter of a 12-gauge copper wire is 0.081 in. The maximum safe current it can 17) carry (in order to prevent fire danger i
Soloha48 [4]

Answer:

0.44m/s

Explanation:

drift velocity=I/nAq

diameter 12 gauge

wire=0.081inches=0.081*2.5=0.2025cm radius=0.10125cm area=pi*R^2 =20/8.5*10^22*3.14*0.10125^2*10^-4*1.6*10^-19*

V = 0.44m/s

6 0
4 years ago
A child has maximum walking speed of 1.6 m/s. What is the length of the child's legs?
guajiro [1.7K]

There's not enough information in the question to calculate the answer.

Knowing the child's walking speed, we would need to know how often s/he takes a step in order to calculate the length of their legs.

6 0
3 years ago
Read 2 more answers
If the frequency of the 13C signal of TMS is 201.16 MHz, the two 13C signals of acetic acid at 179.0 and 20.0 ppm are separated
Lelu [443]

The difference in frequency of the two signals is 1.33 \times 10^{10} \ kHz.

The given parameters;

  • <em>frequency of the 13 C signal = 201.16 MHz</em>

The energy of the 13 C signal located at 20 ppm is calculated as follows;

E = hf\\\\E_1 = h \frac{c}{\lambda} \\\\E_1 =  \frac{(6.626 \times 10^{-34})\times 3\times 10^8}{20 \times 10^{-6}} \\\\E_1 = 9.94 \times 10^{-21} \ J

The energy of the 13 C signal located at 179 ppm is calculated as follows;

E_2 = \frac{hc}{\lambda} \\\\E_2 = \frac{(6.626\times 10^{-34})\times (3\times 10^{8})}{179 \times 10^{-6} } \\\\E_2 = 1.11 \times 10^{-21} \ J

The difference in frequency of the two signals is calculated as follows;

E_1- E_2 = hf_1 - hf_2\\\\E_1 - E_2 = h(f_1 - f_2)\\\\f_1 - f_2 = \frac{E_1 - E_2 }{h} \\\\f_1 - f_2 = \frac{(9.94\times 10^{-21}) - (1.11 \times 10^{-21})}{6.626\times 10^{-34}} \\\\f_1 - f_2 = 1.33 \times 10^{13} \ Hz\\\\f_1 - f_2 = 1.33\times 10^{10} \ kHz

Thus, the difference in frequency of the two signals is 1.33 \times 10^{10} \ kHz.

Learn more here:brainly.com/question/14016376

4 0
3 years ago
A 5 kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N opposing the motion. Calculat
valkas [14]

Answer:

a = 6.4 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration. In this way, we have the following equation.

∑F = m*a

where:

∑F = sum of forces (horizontal force = 40 [N] and friction force = 8 [N])

m = mass of the block = 5 [kg]

a = acceleration [m/s²]

Now replacing:

40-8=5*a\\32 = 5*a\\a=6.4[m/s^{2} ]

Note: the sign of the friction force is negative since this force is acting against the movement of the block.

8 0
3 years ago
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