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saul85 [17]
3 years ago
13

Two cars are sitting still. Car A has a mass of 2000 kilograms. Car B has a mass of 4000 kg. If the goal is to push both cars to

roll at the same speed, describe the force it will take to get Car B to that speed? (Assume everything else is equal: friction & steepness of the road, time, person pushing, etc.)
Physics
1 answer:
astra-53 [7]3 years ago
7 0
Since car B has twice as much mass as car A has, it would require 2x as much force that it would need to push car A down.

If that was kinda confusing lemme say it again,

It would take twice as much that would be needed to push car B down than car A

Since everything is the same, basically two people would need to push down car B and one person for car A

Hope this helps
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Given that ethylene has a λmax of 175nm, butadiene has a λmax of 220nm, and 2-methyl-1,3-butadiene has a λmax or 215nm, what is
Vika [28.1K]

The λmax of 2,3,4-trimethylhexatriene is 280 nm.

Ethylene has a λmax of 175nm.

Butadiene has a λmax of 220nm.

2-methyl-1,3-butadiene has a λmax or 215nm.

1,3,5-hexatriene has a λmax of 258nm.

Woodward's rules, sometimes known as Woodward-Fieser rules (after Louis Fieser) and named after Robert Burns Woodward, are a number of sets of empirically developed principles that aim to forecast the wavelength of the absorption maximum (max) in an ultraviolet-visible spectrum of a certain molecule.

By using the Woodward Fieser rule,

R- (Alkyl Group) .... +5 nm = 5 × 2 = 10

RO- (Alkoxy Group) .. +6 = 6 × 2 = 12

Adding 22nm to the λmax of 1,3,5-hexatriene as it has 2 alkyl groups and 2 alkoxy groups to form 2,3,4-trimethylhexatriene.

The λmax of 2,3,4-trimethylhexatriene is 280 nm.

Learn more about Woodward-Fieser here:

brainly.com/question/16982345

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