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GaryK [48]
3 years ago
11

What is gravitational constant?​

Physics
1 answer:
WITCHER [35]3 years ago
6 0
The constant in Newton's law of gravitation relating gravity to the masses and separation of particles, equal to 6.67 × 10-11N m2 kg-2.
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A 70.0-kilogram man is walking at a speed if 2.0 m/s. What is the kinetic energy?
Paraphin [41]

Answer:

140 J

Explanation:

From the the question, the mass of the man =70.0 kg and the speed at which the man is walking =2.0 m/s.

K.E =  \frac{1}{2}m {v}^{2}

where K.E = the kinetic energy, m=mass and v= speed.

By substitution,

K.E =  \frac{1}{2} \times 70 \times  {2}^{2}

\implies \: K.E = \frac{280}{2}

\implies K.E =140

Hence the kinetic energy of the man is 140J

3 0
3 years ago
If an object is not accelerating, then one knows for sure that it is_____.​
Sauron [17]
The object is maintaining a constant velocity
6 0
4 years ago
True or false if an object has energy it must be moving
Drupady [299]

Answer:

Explanation:

If an object is moving, it is said to have kinetic energy (KE). Potential energy (PE) is energy that is "stored" because of the position and/or arrangement of the object. The classic example of potential energy is to pick up a brick. When it's on the ground, the brick had a certain amount of energy.

3 0
4 years ago
Read 2 more answers
Metals are used in many products because of the characteristics properties that most metals have. Which product requires the hig
nadezda [96]
Alright sounds good buddy
5 0
2 years ago
Physics questions please help me
Ahat [919]
Hi,Find  answers from Task 5

1.(X+4)+(X)+(X+4)+(X)=50cm

4x+8=50cm

4x=42

X=10.5cm

Length=10.5+4=14.5cm

Width=10.5cm

Area= length × width=(10.5/100) × (14.5/100) =0.0152m2

2. Volume of a sphere= 4/3 ×π×r³

4/3 ×π×r³=3.2×10^-6 m³

r³=3.2×10^-6 m³/1.33×π

r³=7.64134761e-7

r=0.00914m

Surface area of the blood drop= 4πr²

=4×3.142×0.00914×0.00914=0.00105m²

3.

Equation of an ideal gas     = PV =n RT  

Equation for pressure, = P= n RT/V

Equation for the volume of an ideal gas= V= n RT/P

If the volume of gas doubles ,V(new)=  2n RT/P

Equation for temperature of an ideal gas, T = PV/n R

If temperature of gas triples, T (new)= 3PV/n R

New Equation for Pressure, = n× R× (3PV/n R)/(2n RT/P)

Pressure factor increase= P(new)/P(old)  ={ n× R× (3PV/n R)/(2n RT/P)}/{ n RT/V}

=3PV²/2n RT
5 0
3 years ago
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