Write one claim about this graph Short answer
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Refer to the diagram shown below.
F = 2000 N, the force exerted on the cannonball
L = 2.41 m, the length of the barrel
V₀ = 83 m/s, the launch velocity
θ = 35°, the launch angle
Let m = the mass of the cannonball.
Let a = the acceleration of the ball when fired.
The net force acting on the ball is
F - mg sinθ = 2000 - 9.8*m*sin(35°) = 2000 - 5.621*m N
Then, from Newton's Law of motion,
F = ma
2000 - 5.621*m = m*a (1)
The launch velocity is V₀ = 8.3 m/s, therefore
V₀² = 2*a*L
(83 m/s)² = 2*(a m/s²)*(2.41 m)
6889 = 4.82*a
a = 6889/4.82 = 1429.25 m/s² (2)
Insert (2) into (1)
2000 - 5.621*m = 1429.25*m
2000 = 1434.871*m
m = 1.394 kg
Answer: 1.394 kg
F = 2000 N, the force exerted on the cannonball
L = 2.41 m, the length of the barrel
V₀ = 83 m/s, the launch velocity
θ = 35°, the launch angle
Let m = the mass of the cannonball.
Let a = the acceleration of the ball when fired.
The net force acting on the ball is
F - mg sinθ = 2000 - 9.8*m*sin(35°) = 2000 - 5.621*m N
Then, from Newton's Law of motion,
F = ma
2000 - 5.621*m = m*a (1)
The launch velocity is V₀ = 8.3 m/s, therefore
V₀² = 2*a*L
(83 m/s)² = 2*(a m/s²)*(2.41 m)
6889 = 4.82*a
a = 6889/4.82 = 1429.25 m/s² (2)
Insert (2) into (1)
2000 - 5.621*m = 1429.25*m
2000 = 1434.871*m
m = 1.394 kg
Answer: 1.394 kg
The slope of the velocity time graph of an object moving with constant acceleration is constant
It will take approximately <u>3 seconds</u> for the center of mass of Object X to reach point J near the bottom of the incline
The reason why the above time value is correct is given as follows:
Known parameters:
Initial velocity of the objects, u = 0
The graph in the question is a straight line graph with data points
(0, 0), (0.5, 1.0), (1.0, 2), (3.0, 6), and (3.5, 7)
Given that the slope of the velocity-time graph is constant, we have that the acceleration is constant and is given as follows;
Therefore;
The acceleration, a ≈ 2 m/s²
The distance from the center of mass of the Object X to the point J near the bottom = 9 m
The equation for distance travelled is given as follows;
Which gives;
t = √9 = 3
The time it will take the center of mass of Object X to reach point J near the bottom of the incline is t = <u>3 seconds</u>
Learn more about motion under constant acceleration here:
