Answer:
True
Explanation:
Sound is all about vibrations.
The source of a sound vibrates, bumping into nearby air molecules which in turn bump into their neighbor's, and so forth.
Answer:

Explanation:
According to the first Newton's law, when a particle moves with constant velocity, the sum of forces on it is zero. So, we have:

Here
is the magnetic force and
is the gravitational force. The velocity of the particle is perpendicular to the magnetic field, so
. Replacing and solving for B:

I have a strange hunch that there's some more material or previous work
that goes along with this question, which you haven't included here.
I can't easily find the dates of Mercury's extremes, but here's some of the
other data you're looking for:
Distance at Aphelion (point in it's orbit that's farthest from the sun):
<span><span><span><span><span>69,816,900 km
0. 466 697 AU</span>
</span>
</span>
</span>
<span>
Distance at Perihelion
(</span></span><span>point in it's orbit that's closest to the sun):</span>
<span><span><span><span>46,001,200 km
0.307 499 AU</span> </span>
Perihelion and aphelion are always directly opposite each other in
the orbit, so the time between them is 1/2 of the orbital period.
</span><span>Mercury's Orbital period = <span><span>87.9691 Earth days</span></span></span></span>
1/2 (50%) of that is 43.9845 Earth days
The average of the aphelion and perihelion distances is
1/2 ( 69,816,900 + 46,001,200 ) = 57,909,050 km
or
1/2 ( 0.466697 + 0.307499) = 0.387 098 AU
This also happens to be 1/2 of the major axis of the elliptical orbit.
Answer:
total stretch of the double-length spring will be 20 cm
Explanation:
given data
length x1 = 10 cm
mass = 1 kg
mass = double = 2 kg
to find out
the total stretch of the double-length spring will be
solution
we can say here spring constant is
k = mg ............1
k is spring constant and m is mass and g is acceleration due to gravity
so for in 1st case and 2nd case with 1 kg mass and 2 kg mass
kx1 = mg .........................2
and
kx2 = 2mg ........................3
x is length
so from equation 2 and 3



x2 = 20
so total stretch of the double-length spring will be 20 cm
Current can vary in different branches of a circuit