Is 7849 a reasonable answer for 49 times 49 why or why not
1 answer:
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Answer:
Yes. The sample size is large enough
H0: μ=170
Ha: μ≠ 170
a) μ= 172.52
b) 10.31
c) yes, the data is distributed around both sides of the mean
d) H0: μ=170 is true
Step-by-step explanation:
a) mean= sum of all sample values/25
(170+167+174+179+179+187+179+183+179 +156+163+156+187+156+167+156+174+170+ 183+ 179+ 174+ 179+ 170+ 159+ 187)/25 = 172.52
b) standard deviation= √(∑(x-μ)²/25)
Using this formula value of standard deviation was computed to be 10.31
c) Least value is 156, difference between least and mean is 16.52
Max value is 187, difference between max and mean is 14.48
A scatter plot shows that number of values higher than mean is 14 and number of values lower than mean is 11. So we can say that data is distributed around mean
d) Null hypthesis is accepted
Test statistic= (sample mean-expected mean)/standard deviation
=(172.52-170)/10.31
= 0.024
P(Z> 0.024)= (1-0.5080)= 0.492
p-value= 2× 0.492= 0.984
Using 5% or 0.05 significance level,
test statistic is greater than significance level so null hypothesis is accepted
Answer:
Number of carnations = 6
Step-by-step explanation:
Let the number of carnations school band buys from florist be x.
Cost of each carnation = $0.50
Total cost for x number of carnations = $0.50x
Also , delivery cost = $15
So, total cost on buying x number of carnations from florist = 0.50x + 15
Now,
School band sells carnations at a price of $3 each.
Total revenue they get get after selling x number of carnations = $3x
We need to find that , when will the cost of the carnations be equal to the revenue from selling them.
i.e 3x = 0.50x + 15
or 3x - 0.50x = 15
or 2.50x = 15
or x =
or x = 6
so on selling 6 carnations cost of carnation reach to the point where it is equal to revenue