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creativ13 [48]
3 years ago
6

What happens to density when you change temperature of an object?

Physics
1 answer:
solong [7]3 years ago
4 0
Most of the substances have higher density in solid state. When we heated solids it change its state to liquid. After a few minutes the liquid will boil and after that it will change to gas. Gaseous state of matter has the lowest density. From this we can conclude that density decreases with increase in temperature.

Note the point: Water has higher density in 4℃, at its liquid state
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What W is the amount of force with which gravity is pulling down on something<br>​
stira [4]

Answer: Weight– the amount of gravity acting on (pulling down on) an object (or mass).

Gravity– a natural force that pulls objects downward.

4 0
3 years ago
A 0.60 kg soccer ball at rest is kicked by a player who has a mass of 50.0 kg. The final speed of the soccer ball after being ki
Bezzdna [24]

Answer: The momentum is 500.

Explanation: The equation for momentum is p=mv, so you would multiply the mass of the player(50kg) and the speed of the ball(10m/s) to get 500.

8 0
3 years ago
Read 2 more answers
Please help I will fail
Mandarinka [93]

Answer:

6. A

7. C

8. B

9. The average speed is the distance (a scalar quantity) per time ratio. Speed is ignorant of direction. The average velocity is the displacement or position change (a vector quantity) per time ratio.

4 0
3 years ago
A major league baseball has a mass of 0.145 kg.
galben [10]

The momentum of the ball when it hits the ground is 4.89 kg.m/s.

The given parameters;

  • <em>mass of the baseball, m = 0.145 kg</em>
  • <em>height of fall of the ball, h = 58 m</em>

The final velocity of the ball when it hits the ground is calculated as follows;

v_f ^2 = v_0^2 + 2gh\\\\v_f^2 = 0 + 2gh\\\\v_f^2 = 2gh\\\\v_f = \sqrt{2gh} \\\\v_f = \sqrt{2\times 9.8 \times 58}\\\\v_f = 33.72 \ m/s

The momentum of the ball when it hits the ground is calculated as follows;

P = mv

P = 0.145 x 33.72

P = 4.89 kg.m/s

Thus, the momentum of the ball when it hits the ground is 4.89 kg.m/s.

Learn more here:brainly.com/question/22035809

6 0
3 years ago
Use Hooke's Law to determine the work done by the variable force in the spring problem. Nine joules of work is required to stret
natima [27]

Answer:

29.16 J

Explanation:

From Hook's law,

W = 1/2(ke²)..................... Equation 1

Where W = work done, k = Spring constant, e = extension.

Given: W = 9 J, e = 0.5 m.

Substitute into equation 1

9 = 1/2(k×0.5²)

Solve for k

k = 18/0.5²

k = 72 N/m.

The work done required to stretch the spring by additional 0.4 m is

W = 1/2(72)(0.4+0.5)²

W = 36(0.9²)

W = 29.16 J.

6 0
3 years ago
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