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3 years ago

12

What is the value of work done on an object when a 0.1x102-newton force moves it 30 meters and the angle between the force and t

he
displacement is 25°?

1 answer:

disa [49]3 years ago

3 0

Answer:306joules

Explanation:

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A 55 meter rope is lying on the floor and has has a weight of 4040 N in total. How much work is required to lift up one end of t

Kazeer [188]

Answer:

Explanation:

Given

Length of rope $L=55\ m$

Weight of rope $W=4040\ N$

weight density $\lambda =\frac{4040}{55}=73.45\ N/m$

Work done to lift rope 33 m

$W=\int_{0}^{33}\lambda hdh$

$W=\int_{0}^{33}73.45hdh$

$W=73.45\left [ \left ( \frac{h^2}{2}\right )\right ]^{33}_0$

$W=39.993\ kJ$

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3 years ago

A rifle fires a bullet at a velocity of 78 m/s, 40 degrees above the horizontal. Determine the height (h) above the starting pos

qwelly [4]

Answer:

H = Vy t - 1/2 g t^2 height of an object with an initial "vertical" velocity

at t sec after firing

Vy = 78 m/s * sin 40 = .643 * 78 m/s = 50.1 m/s

H = 50.1 * 6 - 1/2 * 9.8 * 6^2 = 300 m - 176 m = 124 m

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3 years ago

Three kids are riding on a snow sled traveling horizontally without friction at 19.8 m/s. The masses of Kid A, B, and C are 42.8

Kamila [148]

Answer:

34.6 m/s

Explanation:

From conservation of momentum, the sum of initial and final momentum are equal. Momentum is a product of mass and velocity. Initial mass will be 42.8+31.5+25.9=100.2 kg

Final mass will be 31.5+25.9=57.4 kg

From formula of momentum

M1v1=m2v2

Making v2 the subject of the formula then

$V2=\frac {M1v1}{m2}$

Substitute 100.2 kg for M1, 19.8 m/s fkr v1 and 57.4 kg for m2 then

$V2=\frac {100.2 kg\times 19.8 m/s}{57.4 kg}=34.56376 m/s\approx 34.6 m/s$

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Answer:

please write neater

Explanation:

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4 years ago

A book is pushed across the table by a student. The student stops pushing on the book and the book slows down and stops. The for

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A. inertia

Because it has to do with the motion of something, especially if it changes its pace. In this example, the book's motion, when sliding on the table, decreased because of less force being given off from the student.

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