Answer:
65.87 s
Explanation:
For the first time,
Applying
v² = u²+2as.............. Equation 1
Where v = final velocity, u = initial velocity, a = acceleration, s = distance
From the question,
Given: u = 0 m/s (from rest), a = 1.99 m/s², s = 60 m
Substitute these values into equation 1
v² = 0²+2(1.99)(60)
v² = 238.8
v = √238.8
v = 15.45 m/s
Therefore, time taken for the first 60 m is
t = (v-u)/a............ Equation 2
t = (15.45-0)/1.99
t = 7.77 s
For the final 40 meter,
t = (v-u)/a
Given: v = 0 m/s(decelerates), u = 15.45 m/s, a = -0.266 m/s²
Substitute into the equation above
t = (0-15.45)/-0.266
t = 58.1 seconds
Hence total time taken to cover the distance
T = 7.77+58.1
T = 65.87 s
The word displacement implies that an object has moved, or has been displaced. Displacement is defined to be the change in position of an object.
Displacement is defined as the act of moving someone or something from one position to another or the measurement of the volume replaced by something else
Answer:the first one was x
the second one is y
Explanation:
Answer:a)1.11×10^-21Nm
b) 1.16×10^-3m
Explanation:see attachment
v = 
and
a = 
We have acceleration and velocity so:
3 =
88.3 =
In the acceleration equation we can isolate for v and then plug it back into the other equation to solve...
So...
Divide by three and
t = 29.4 s
