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3 years ago

During a neap tide, which phase could the moon be in? select all that apply

Physics

2 answers:

Ne4ueva [31]3 years ago

8 0

Answer:

b. third quarter

c. first quarter

Explanation:

Neap tides happen in the third and first quarter of the moon phase, when the moon appears to be half full, this is because of the position of the moon and the gravitational force of the moon attracting the tides along with the gravitational force of the sun, tha causes high tides on new, and full phases, but the third quarter and first quarter, the moon makes a 90º line with the solar gravitational forces, cancelling out both forces making it low tide or neap tide.

snow_lady [41]3 years ago

4 0

Hello,

Here is your answer:

The proper answer to this question is option B "third quarter".

Here is how:

Neap tides are caused when the moon is three thirds full which causes the current to up rise therefore making a neap tide.

Your answer is B.

If you need anymore help feel free to ask me!

Hope this helps!

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An 81.5-kg man stands on a horizontal surface.

OLga [1]

Answer:

a)V= 0.0827 m³

b)P=181.11 x 10² N/m²

Explanation:

Given that

m = 81.5 kg

Density ,ρ = 985 kg/m³

As we know that

Mass = Volume x Density

81.5 = V x 985

V= 0.0827 m³

The force exerted by weight = m g

F= m g= 81.5 x 10 = 815 N ( Take ,g= 10 m/s²)

Area ,A= 4.5 x 10⁻² m²

The Pressure P

$P=\dfrac{F}{A}$

$P = \dfrac{815}{4.5\times 10^{-2}}\ N/m^2$

P=181.11 x 10² N/m²

7 0

3 years ago

A 1560-kilogram truck moving with a speed of 28.0 m/s runs into the rear end of a 1070-kilogram stationary car. If the collision

Nimfa-mama [501]

Answer:

Δ KE = 249158.6 kJ

Explanation:

given data

Truck mass M = 1560 Kg

Truck initial speed, u = 28 m/s

mass of car m = 1070 Kg

initial speed of car u1 = 0 m/s

solution

first we get here final speed by using conservation of momentum that is express as

Mu = (M+m) V .......................1

put here value we get

1560 × 28 = (1560 + 1070 ) V

solve it we get

final speed V = 16.60 m/s

and

Change in kinetic energy will be here

Δ KE = $\frac{1}{2} Mu^2 - \frac{1}{2}(M+m)V^2$ .................2

put here value and we get

Δ KE = $\frac{1}{2}\times 1560\times 28^2 - \frac{1}{2}\times (1560 + 1070)\times 16.60^2$

solve it we get

Δ KE = 249158.6 kJ

6 0

3 years ago

How far does a car travel in 90 seconds if it’s traveling 55 m/s? Show equation

podryga [215]

You just said the car is traveling at the speed of 55 m/s. If I understand this correctly, that means the car will cover:

55 meters in the first second,

55 meters in the 2nd second,

55 meters in the 3rd second,

55 meters in the 4th second,

55 meters in the 5th second,

55 meters in the 87th second,

55 meters in the 88th second,

55 meters in the 89th second, and

55 meters in the 90th second.

That's 55 meters 90 times. If you just move these words around a little bit, it says "90 times 55 meters" . . . a pretty simple arithmetic problem.

The equation is . . . Distance = (55 m/s) times (time, in seconds) .

I get 4,953 meters. You should check me on this.

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3 years ago

Explain what is meant by “field” and compare the properties of gravitational, electric, and magnetic forces in terms of particle

Tema [17]

A field is the description of a spatial region, the force exerted on objects by a field is a field force.
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3 years ago

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SOVA2 [1]

Answer:

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Explanation:

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3 years ago

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