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valentina_108 [34]
3 years ago
7

Describe some precautions needed to increase the safety of participants in the sports of football.

Physics
1 answer:
OLga [1]3 years ago
8 0
Football is a popular ball game and so many people play football these days. Been a contact game, there is no way players will not sustain injuries, but this can be reduced to the lowest point by taking some precautions.
The precautions that could be taken include the following:
Wear the right shoes.
Wear shin guard and soccer socks.
Use the right and properly fitted equipment [helmets, shoulder pads, googles, mouth-guards, etc]. All these equipment should be made for the soccer sport.

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Where does groundwater come from?
jek_recluse [69]
Groundwater is the water found underground in the cracks and spaces in soil, sand and rock. It is stored in and moves slowly through geologic formations of soil, sand and rocks called aquifers.


Hope this helps.


Please mark as brainliest..........
4 0
3 years ago
Read 2 more answers
An aircraft performs a maneuver called an "aileron roll." During this maneuver, the plane turns like a screw as it maintains a s
Dmitriy789 [7]

Answer:

0.17724 m/s²

Explanation:

D = Diameter of roll = Length of wing = 11 m

T = Time it takes to complete the circle = 35 s

Velocity

v=\frac{2\pi R}{T}\\\Rightarrow v=\frac{\pi D}{T}\\\Rightarrow v=\frac{\pi\times 11}{35}\\\Rightarrow v=0.98735\ m/s

Acceleration

a=\frac{v^2}{R}\\\Rightarrow a=\frac{0.98735^2}{\frac{11}{2}}\\\Rightarrow a=0.17724\ m/s^2

Acceleration of the tip of the plane is 0.17724 m/s²

3 0
3 years ago
1. A stationary 50 tonne submarine fires a missile of mass 40kg at
White raven [17]

The velocity of the submarine immediately after firing the missile is 0.0104 m/s

Explanation:

Mass of the submarine M=50 tonne=50\times 1000=50000kg

Mass of the missile m=40  kg

velocity of the missile v= 13m/s

we have to calculate the velocity of the submarine after firing

This is the recoil velocity and its expression is derived from the law of conservation of momentum

recoil velocity of the submarine

V=-mv/M\\=-40\times 13/50000\\=0.0104 m/s

8 0
3 years ago
You have a 3.00-liter container filled with N₂ at 25°C and 4.45 atm pressure connected to a 2.00-liter container filled with Ar
LuckyWell [14K]

Answer : The final pressure in the two containers is, 2.62 atm

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

Thus, the expression for final pressure in the two containers will be:

PV=P_1V_1+P_2V_2

P=\frac{P_1V_1+P_2V_2}{V}

where,

P_1 = pressure of N₂ gas = 4.45 atm

P_2 = pressure of Ar gas = 2.75 atm

V_1 = volume of N₂ gas = 3.00 L

V_2 = volume of Ar gas = 2.00 L

P = final pressure of gas = ?

V = final volume of gas = (4.45 + 2.75) L = 7.2 L

Now put all the given values in the above equation, we get:

P=\frac{(4.45atm)\times (3.00L)+(2.75atm)\times (2.00L)}{7.2L}

P=2.62atm

Thus, the final pressure in the two containers is, 2.62 atm

8 0
3 years ago
Help on matching please, struggling on it. Even just 1 or 2 would help
n200080 [17]

Answer:

7. free fall -- h. 9.8m/s^2

3. Velocity -- x. 60 km/hr west

6. Acceleration -- d. change in velocity/time

8. Centrifugal --  s. towards the centre

13. Work done --w. Force * displacement

5. Uniform circular motion --j. spin cycle in washer

18. Power -- r. kW an hour

7. g -- a. 10N

hope this helps

6 0
2 years ago
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