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Shalnov [3]
3 years ago
12

A positive charge of 1 µC is taken from points A & B such that VA-VB = 100 V. Then the

Physics
1 answer:
Lunna [17]3 years ago
4 0

Explanation:

It is given that,

Let Charge of 1\ \mu C is taken from points A & B such that V_A-V_B=1000\ V.

We need to find the energy of charge. Electric potential is defined as the work done per unit of electric charge. So,

W=(V_B-V_A)q\\\\W=-1000\times 10^{-6}\\\\W=E=-10^{-3}\ J

So, the energy of charge decreases by 10^{-3}\ J. Hence, the correct option  is (a).

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Determine qual é a carga elétrica de um corpo que possui 1 milhão de partículas?
MaRussiya [10]

Answer:

This can be translated to:

"find the electrical charge of a body that has 1 million of particles".

First, it will depend on the charge of the particles.

If all the particles have 1 electron more than protons, we will have that the charge of each particle is q = -e = -1.6*10^-19 C

Then the total charge of the body will be:

Q = 1,000,000*-1.6*10^-19 C = -1.6*10^-13 C

If we have the inverse case, where we in each particle we have one more proton than the number of electrons, the total charge will be the opposite of the one of before (because the charge of a proton is equal in magnitude but different in sign than the charge of an electron)

Q = 1.6*10^-13 C

But commonly, we will have a spectrum with the particles, where some of them have a positive charge and some of them will have a negative charge, so we will have a probability of charge that is peaked at Q = 0, this means that, in average, the charge of the particles is canceled by the interaction between them.

7 0
3 years ago
A car travels initially at 24 m/s, until it enters the highway. If the car accelerates at 4 m/s^2 for a 96 meters, what is the c
marishachu [46]
  • initial velocity=u=24m/s
  • Acceleration=a=4m/s^2
  • Distance=s=96m
  • Final velocity=v

Using 3rd equation of kinematics

\boxed{\Large{\sf v^2-u^2=2as}}

\\ \Large\sf\longmapsto v^2=u^2+2as

\\ \Large\sf\longmapsto v^2=24^2+2(4)(96)

\\ \Large\sf\longmapsto v^2=576+768

\\ \Large\sf\longmapsto v^2=1344

\\ \Large\sf\longmapsto v=\sqrt{1344}

\\ \Large\sf\longmapsto v=36.6m/s

3 0
3 years ago
Two cars start from rest at a red stop light. When the light turns green, both cars accelerate forward. The blue car accelerates
saul85 [17]
First, create an illustration of the motion of the two cars as shown in the attached picture. The essential equations used is

For constant acceleration:
a = v,final - v,initial /t

The solutions is as follows:

 a = v,final - v,initial /t
 3.8 = (v - 0)/2.8 s
 v = 10.64 m/s
 After 2.8 seconds, the speed of the blue car is 10.64 m/s.

4 0
3 years ago
a 75-kg refrigerator is located on the 70th floor of a skyscraper (300 meters above ground). what is the potential energy of the
mart [117]
Here, you can calculate it's potential energy with respect to ground.
We know, U = mgh
Here, m = 75 Kg
g = 9.8 m/s²       [ constant value for earth system ]
h = 300 m

Substitute their values into the expression:
U = 75 × 9.8  × 300
U = 220500 J

In short, Your Final Answer would be 220,500 J 

Hope this helps!
8 0
3 years ago
Where is planet mercury located in the solar system?
olya-2409 [2.1K]
Its orbit is between Venus' and the sun.
7 0
3 years ago
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