Answer:
Option B
Technician B
Explanation:
Wheel tire assembly is considered as maximum of the un-sprung weight hence technician A is incorrect while it’s true that with lower sprung weight, it is easier to handle the vehicle on difficult and irregular surface conditions. This implies that technician B is correct.
Answer:
7400 m/s
Explanation:
Centripetal acceleration = gravity
v² / r = GM / r²
v = √(GM / r)
Given:
G = 6.67×10⁻¹¹ m³/kg/s²
M = 5.98×10²⁴ kg
r = 9.8×10⁵ + 6.357×10⁶ = 7.337×10⁶ m
v = √(6.67×10⁻¹¹ (5.98×10²⁴) / (7.337×10⁶))
v = 7400
The orbital velocity is 7400 m/s.
The distance the car has skidded if it had been moving at 40.0 m/s is 27.2m
The linear force acting on the car is opposed by the frictional force. Hence;
m is the mass of the car
a is the acceleration
is the coefficient of friction
R is the normal force
Given the following parameters
Get the distance the car has skidded if it had been moving at 40.0 m/s
Hence the distance the car has skidded if it had been moving at 40.0 m/s is 27.2m
Learn more here: brainly.com/question/15246552