Answer : The amount of air added to the tank will be, 1.2062 Kg.
Explanation :
First we have to calculate the volume of air by using ideal gas equation.
where,
= initial pressure of air =
conversion used :
= initial temperature of air =
conversion used :
= initial volume of air = ?
= initial mass of air =
conversion used :
R = gas constant = 0.0821 L.atm/mole.K
M = molar mass of air
Now put all the given values in the above expression, we get:
Now we have to calculate the final amount of air by using ideal gas equation.
where,
= final pressure of air =
= final temperature of air =
= final volume of air =
= final mass of air = ?
R = gas constant = 0.0821 L.atm/mole.K
M = molar mass of air
Now put all the given values in the above expression, we get:
Now we have to calculate the amount of air added to the tank.
conversion used : (1 Kg = 1000 g)
Hence, the amount of air added to the tank will be, 1.2062 Kg.