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Ber [7]
3 years ago
11

0.000068 g Express your answer as an integer.

Chemistry
2 answers:
Fittoniya [83]3 years ago
6 0

<u>Answer:</u> This unit is equal to 68\mu g

<u>Explanation:</u>

An integer is defined as a whole number which can be positive, negative or zero. This cannot be written in fractions or decimals.

The given number in the question is written in decimal form. So, to convert it into a integer, we will convert the unit of 'grams' to 'micrograms'.

To convert grams into micrograms, we use the conversion factor:

1g=10^6\mu g

Converting 0.000068 g into micrograms, we get:

0.000068g=(0.000068\times 10^6)\mu g=68\mu g

The above number is a positive integer. Hence, this unit is expressed in integer and is equal to 68\mu g

ivann1987 [24]3 years ago
5 0
6.8x10^5? Scientific notation
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A sample of CO2 weighing 86.34g contains how many molecules?
irakobra [83]

Answer:

1.181 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

86.34 g CO₂

<u>Step 2: Identify Conversion</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

<u />86.34 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} ) = 1.18141 × 10²⁴ molecules CO₂

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

1.18141 × 10²⁴ molecules CO₂ ≈ 1.181 × 10²⁴ molecules CO₂

4 0
3 years ago
A 0.175 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.27° in a 1-dm sample
-BARSIC- [3]

Answer:

The specific rotation of D is 11.60° mL/g dm

Explanation:

Given that:

The path length (l) =  1 dm

Observed rotation (∝) = + 0.27°

Molarity = 0.175 M

Molar mass = 133.0 g/mol

Concentration in (g/mL) = 0.175 mol/L × 133.0 g/mol

Concentration in (g/mL) = 23.275 g/L

Since 1 L = 1000 mL

Concentration in (g/mL) = 0.023275 g/mL

The specific rotation [∝] = ∝/(1×c)

= 0.27°/( 1  dm ×  0.023275 g/mL )

= 11.60° mL/g dm

Thus, the specific rotation of D is 11.60° mL/g dm

3 0
3 years ago
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shusha [124]

Answer:

kkkkkkkiuouo 9o                            

Explanation:

8 0
2 years ago
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