Surface area of cube = 6 * (side)^2
side^2 = surface area / 6
side = sqrt (surface area / 6)
For the cube with area 1200 square inches:
side = sqrt(surface area / 6)
side = sqrt(1200 / 6)
side = 14.1421 inches
For the cube with area 768 square inches:
side = sqrt(surface area / 6)
side = sqrt(768 / 6)
side = 11.3137 inches
difference between the two lengths = 14.1421 - 11.3137 = 2.8284 inches
Based on the above calculations, the side of the cube with surface area 1200 square inches is 2.8284 inches longer than the side of the cube with surface area 768 square inches
You could say 8r+2 times s +4 or –5x2y4
Answer: $48,366.78
Step-by-step explanation:
3000(1+0.04/4) 4t
The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium.
<h3>Can this atrium be built in the rectangular plot of land?</h3>
The atrium with the <em>maximum allowable</em> radius (<em>R</em>), in feet, is represented in the image attached. The <em>real</em> atrium is possible if and only if the <em>real</em> radius (<em>r</em>) is less than the maximum allowable radius and therefore, the <em>real</em> volume (<em>V</em>), in cubic feet, must be less than than <em>maximum possible</em> volume (<em>V'</em>), in cubic feet.
First, we calculate the volume occupied by the maximum allowable radius:
<em>V' =</em> (8 · π / 3) · (45 ft)³
<em>V' ≈</em> 763407.015 ft³
The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium. ![\blacksquare](https://tex.z-dn.net/?f=%5Cblacksquare)
To learn more on volumes, we kindly invite to check this verified question: brainly.com/question/13338592