Im sorry i dont understand the question.. Is there another form of the question you can give me?
Subtract the 2nd row from the 1st row
5x = 5
Solve for x in the equation above
x = 1
Substitute x = 1 into any of the two equations above
Let's pick the first equation; 4x + 3y = -5
4 * 1 + 3y = -5
Solve for y in the equation above
y = -3
Therefore,
<u>x = 1</u>
<u>y = -3</u>
3x -7 = 14
3x - 7 (+7) = 14 (+7)
3x = 21
3x/3 = 21/3
x = 7
hope this helps
Answer:
first do:
60mph * 4 hours= 240mi
Let D = the distance the passenger train has to
travel to catch the freight train
Start a stopwatch when the passenger train leaves
Let t = the time on the stopwatch when they meet
Equation for freight train:
d-240=60t
Equation for passenger train:
d=100t
all together:
100t-240=60t
we can do 100t-60t because they both have (t)= 40t
40t=240 *now divide 240 by 40= 6
THEN do:
D= 100mph x 6= 600mi
They will meet 600 mi from the station
to check:
d-240=60t x 6
600-240= 360
60 x 6= 360
360=360
