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serg [7]
3 years ago
10

Next month, Tokuji's monthly net income will increase to

Mathematics
1 answer:
shepuryov [24]3 years ago
7 0

The correct answer on Edge is A: $20

Hope I could help!!

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2 cards are drawn from a standard deck without replacement. What is the probability that at least one of the cards drawn is an a
olya-2409 [2.1K]

Answer:

<h2>The answer is 0.1493.</h2>

Step-by-step explanation:

In a standard deck there are 52 cards in total and there are 4 aces.

Two cards can be drawn from the 52 cards in ^{52}C_2 = \frac{52!}{50!\times2!} = 51\times26 ways.

There are (52 - 4) = 48 cards rather than the aces.

From these 48 cards 2 cards can be drawn in ^{48}C_2 = \frac{48!}{46!\times2!} = 47\times24 ways.

The probability of choosing 2 cards without aces is \frac{47\times24}{51\times26} = \frac{188}{221}.

The probability of getting at least one of the cards will be an ace is 1 - \frac{188}{221} = \frac{33}{221} = 0.1493.

6 0
3 years ago
————PLEASE HELP————-
GuDViN [60]

Answer:

The diameter of Circle P is the same length as the radius of Circle Q.

Step-by-step explanation:

The radius of Circle Q is half of 52cm. So you would divide 52 by 2 and get 26cm as the radius of Circle Q. Therefore, the length of the diameter of Circle P is the same length as the radius of Circle Q.

4 0
3 years ago
Write the equation for the line that passes through (2, -4) and is
Kryger [21]

Answer: y= x-2

Step-by-step explanation:

Perpendicularity entails the slope of line a is -1 divided by the slope of line b

m1= (-1/m2)

From y=Mx +c

We compare with x-4y=7

y=(1/4)x-7/4

Meaning m2= 1/4

m1= -1/(1/4)= -1*4= -4

((y-y1)/(x-x1))= ((y2-y1)/(x2-x1))=m1

x1= 2, y1= -4

((y-(-4))/(x-2))= -4

((y+4)/(x-2))= -4

Cross multiply

y+4= -4(x-2)

y= x-2

3 0
3 years ago
The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of
romanna [79]

Answer: a) \dfrac{3}{874}

b) \dfrac{30}{3059}

c) \dfrac{3575}{12236}

Step-by-step explanation:

Given : Number of students : 11

Number of faculty members : 13

Total persons : 11+13=24

Total number of ways to structure a jury of six people from a group of 24 people :-

^{24}C_{6}=\dfrac{24!}{6!(24-6)!}=134596

a) Number of ways of selecting a jury of all​ students :-

^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462

Then , the probability of selecting a jury of all​ students :-

\dfrac{462}{134596}=\dfrac{3}{874}

b) Number of ways of selecting a jury of all​ faculty :-

^{13}C_{6}=\dfrac{13!}{6!(13-6)!}=462

Then , the probability of selecting a jury of all​ students :-

\dfrac{1716}{134596}=\dfrac{30}{3059}

c) Number of ways of selecting a jury of two students and four ​faculty :-

^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325

Then , the probability of selecting a jury of all​ students :-

\dfrac{39325}{134596}=\dfrac{3575}{12236}

3 0
3 years ago
7f+g=5 solve for g? It's very difficult
Vika [28.1K]

In this case 'g' would be 5 - 7f

8 0
3 years ago
Read 2 more answers
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